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Curious&TheNon
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Homework Statement
A 12V car battery is capable of storing 3.51 kWh of electric energy. For a certain electric car to maintain a speed of 48.3 km/hr, it must develop 10.7 kW of power. If this car is run by 11 batteries which are 90.5% efficient, how far can this car travel, at the desired speed, between recharges?
V= 48.3 m/s (yes constant motion)
P=10700W
efficiency= 90.5%
Each battery capacity= 3510W
Uses 11 batteries
Homework Equations
E= (Wo / Wi ) *100[/B]
E= .5 * m * v^2
W= P*t
The Attempt at a Solution
1. Since its going at a constant velocity, i can find the mass. Using the Energy kinetic formula.
2.Finding the mass i can plug it into the efficiency formula to get its work output.
3. its using 11 batteries that are 90.5% efficient. So on the denominator of the efficiency formula it would be 11* 3510W because each capacity is 3.51kWh.
5.the numerator would be the Energy kinetic formula * 100 and then the efficiency would be 90.5%
6. Getting the time i could multiply it with the velocity to get its distance?