- #1
Ryan Walkowski
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<< Mentor Note -- Thread moved as requested >>
I am trying to complete a mock paper for an upcoming assessment. The mock comes with the answers supplied in bold under the question yet I am having trouble understanding how the answers are obtained. I know that the law states that the sum of all emfs equals all the sums of the voltage drops and i have looked at several online articles but they seem to be very complex for what I need to understand. I am hoping someone can explain using the example I have. I am not sure how the arrows play a part in this either
EDIT: After much banging my head i have come up with the following.Can someone comment if this is correct and if there is a more excepted way of writing it out:
ΣV=0
B-E = -2V
E-D = +10V
D-C = -5V
BE+ED+DC = +3
∴ C-B = 3V
And
ΣV=0
B-E = -2
E-F = +8
A-B = 0
BE+EF+AB = +6
∴ F-A = 6V
I am trying to complete a mock paper for an upcoming assessment. The mock comes with the answers supplied in bold under the question yet I am having trouble understanding how the answers are obtained. I know that the law states that the sum of all emfs equals all the sums of the voltage drops and i have looked at several online articles but they seem to be very complex for what I need to understand. I am hoping someone can explain using the example I have. I am not sure how the arrows play a part in this either
EDIT: After much banging my head i have come up with the following.Can someone comment if this is correct and if there is a more excepted way of writing it out:
ΣV=0
B-E = -2V
E-D = +10V
D-C = -5V
BE+ED+DC = +3
∴ C-B = 3V
And
ΣV=0
B-E = -2
E-F = +8
A-B = 0
BE+EF+AB = +6
∴ F-A = 6V
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