MHB KRISTINE's question at Yahoo Answers (Set inclusion)

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To prove that A is a subset of C given that A is a subset of the union of B and C, and that the intersection of A and B is empty, one can use a contradiction approach. If an element x belongs to A, it must belong to either B or C. However, if x were in B, it would contradict the condition that A and B have no elements in common. Therefore, it must be true that x is in C, confirming that A is indeed a subset of C. This logical deduction effectively demonstrates the relationship between the sets.
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Hello KRISTINE,

By hypothesis, $(i)\;A\subset B\cup C\quad(ii)\;A\cap B=\emptyset$

If $x\in A$, then (by $(i)$) $x\in B$ or $x\in C$.

Suppose $x\in B$. Then, (by $(ii)$) $x\not \in A$ which contradicts the hypothesis $x\in A$. So, necessarily $x\in C$. We have proven $A\subset C$.
 
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