Kyra's question at Yahoo Answers regarding linear difference equations

[MarkFL]

Here is the question:

Math hmk help asap?

help.,, Homework .,, thank you

If the second differences are the same, then the function is:
A. linear
B. quadratic
C. exponential
D. neither

Here is a link to the question:

Math hmk help asap? - Yahoo! Answers

I have posted a link there to this topic so the Op can find my response.

 

[MarkFL]

Re: Kyra's question at Yahoo! Answers regardin linear difference equations

Hello Kyra,

Let the $n$th term of the sequence be given by $A_n$. If the second difference is constant, then we may state:

\(\displaystyle \left(A_{n}-A_{n-1} \right)-\left(A_{n-1}-A_{n-2} \right)=k\) where \(\displaystyle 0\ne k\in\mathbb{R}\)

Combining like terms, we may arrange this as the inhomogeneous linear recurrence:

(1) \(\displaystyle A_{n}=2A_{n-1}-A_{n-2}+k\)

We may increase the indices by 1, to prepare for symbolic differencing:

(2) \(\displaystyle A_{n+1}=2A_{n}-A_{n-1}+k\)

Subtracting (1) from (2), we obtain the homogeneous linear recurrence:

\(\displaystyle A_{n+1}=3A_{n}-3A_{n-1}+A_{n-2}\)

The characteristic equation is then:

\(\displaystyle r^3-3r^2+3r-1=(r-1)^3=0\)

Since the root $r=1$ is of multiplcity 3, we know the closed form will be:

\(\displaystyle A_n=k_1+k_2n+k_3n^2\)

We see then that the closed form is quadratic, hence B is the answer.

To Kyra and any other guest viewing this topic, I invite and encourage you to post other difference equation problems in our http://www.mathhelpboards.com/f15/ forum.

Best Regards,

Mark.