Lagrange optimization: cylinder and plane intersects,

In summary, the given cylinder and plane intersect in an ellipse. Using the equations $f(x)$, $h(x)$, and $g(x)$, a system of equations is set up to find the point on the ellipse furthest from the origin. Solving the system results in the point $(-1, 0, 2)$, rather than the incorrect point $(1, 0, 0)$.
  • #1
a255c
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Homework Statement



The cylinder x^2 + y^2 = 1 intersects the plane x + z = 1 in an ellipse. Find the point on the ellipse furthest from the origin.

Homework Equations



$f(x) = x^2 + y^2 + z^2$

$h(x) = x^2 + y^2 = 1$

$g(x) = x + z = 1$

The Attempt at a Solution



$\langle 2x, 2y, 2z \rangle = \lambda\langle2x, 2y,0\rangle + \mu\langle1,0,1\rangle$

This results in the equations:

$2x = 2x\lambda + \mu$

$2y = 2y\lambda$

$2z = \mu$

Then $\lambda = 1$, then $2x = 2x + \mu$, then $0 = \mu$, so then $z = 0$.

Then $x + z = 1$, so $x = 1$.

And then $1^2 + y^2 = 1$, so $y = 0$, so then I conclude that the point where this ellipse is furthest from the origin is $(1,0,0)$.

This is wrong. The answer should be $(-1,0,2)$
 
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  • #2
You'll have a much better chance of replies if you fix up the Latex. You need to double the dollar signs, or if you don't want an equation on a line by itself replace the dollar sign with a double hash(#).
 
  • #3
a255c said:

Homework Statement



The cylinder x^2 + y^2 = 1 intersects the plane x + z = 1 in an ellipse. Find the point on the ellipse furthest from the origin.

Homework Equations



$f(x) = x^2 + y^2 + z^2$

$h(x) = x^2 + y^2 = 1$

$g(x) = x + z = 1$

The Attempt at a Solution



$\langle 2x, 2y, 2z \rangle = \lambda\langle2x, 2y,0\rangle + \mu\langle1,0,1\rangle$

This results in the equations:

$2x = 2x\lambda + \mu$

$2y = 2y\lambda$

$2z = \mu$

Then $\lambda = 1$, then $2x = 2x + \mu$, then $0 = \mu$, so then $z = 0$.

Then $x + z = 1$, so $x = 1$.

And then $1^2 + y^2 = 1$, so $y = 0$, so then I conclude that the point where this ellipse is furthest from the origin is $(1,0,0)$.

This is wrong. The answer should be $(-1,0,2)$

The equation ##2y = 2y \lambda## implies either ##\lambda = 1## or ##y = 0##.

Note how my LaTeX comes out properly, unlike yours. That is because I used "# # ... # #", but with no space between the two #'s at the start and the end. Had I used $...$ instead it would have come out a mess, like yours. LaTeX/TeX works a bit differently on this Forum than it does in native form.
 

FAQ: Lagrange optimization: cylinder and plane intersects,

1. What is Lagrange optimization and how does it relate to cylinders and planes?

Lagrange optimization is a mathematical technique used to find the maximum or minimum value of a multivariable function subject to constraints. In the case of cylinders and planes, it is used to find the shortest distance between the two intersecting objects.

2. What are the steps involved in Lagrange optimization for a cylinder and plane intersection?

The steps involved in Lagrange optimization for a cylinder and plane intersection are:1. Set up the objective function, which is the expression for the distance between the cylinder and plane.2. Set up the constraint function, which is the equation of the cylinder.3. Use the Lagrange multiplier method to find the critical points.4. Solve the system of equations to find the coordinates of the critical points.5. Plug in the coordinates to the objective function to find the minimum distance.

3. Can Lagrange optimization be applied to any shape of cylinder and plane?

Yes, Lagrange optimization can be applied to any shape of cylinder and plane as long as the equations of the objects are known. However, the complexity of the equations may make the optimization process more difficult.

4. What are the practical applications of Lagrange optimization for cylinder and plane intersections?

Lagrange optimization for cylinder and plane intersections is commonly used in engineering and physics, such as in the design of pipes and tunnels. It can also be applied in computer graphics to create more realistic 3D models.

5. Are there any limitations or drawbacks to using Lagrange optimization for cylinder and plane intersections?

One limitation of Lagrange optimization for cylinder and plane intersections is that it assumes the objects are perfectly smooth and do not have any irregularities or imperfections. In real-world scenarios, this may not always be the case, leading to less accurate results.

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