MHB Lamps's question at Yahoo Answers about the Intermediate Value Theorem

  • Thread starter Thread starter Fernando Revilla
  • Start date Start date
  • Tags Tags
    Theorem Value
AI Thread Summary
The discussion addresses the application of the Intermediate Value Theorem (IVT) to find intervals containing roots for two equations. For the first equation, sin(x) = 6x + 5, it is established that f(x) = sin x - 6x - 5 is continuous, with f(-1) > 0 and f(0) < 0, indicating a root exists in the interval (-1, 0). For the second equation, ln(x) + x^2 = 3, g(x) = ln x + x^2 - 3 is continuous on (0, +∞), with g(1) < 0 and g(2) > 0, confirming a root in the interval (1, 2). The responses effectively demonstrate the use of the IVT to locate roots within specified intervals. This method highlights the importance of continuity in applying the theorem to find solutions.
Fernando Revilla
Gold Member
MHB
Messages
631
Reaction score
0
Here is the question:

use the IVT to find the an interval of length one that contains a root of the equation
a) sin(x) = 6x + 5

b) ln(x) + x^2 = 3

Here is a link to the question:

Intermediate value theorem? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
Mathematics news on Phys.org
Hello lamp,

(a) Denote f(x)=\sin x-6x-5. Clearly, f in continuos in \mathbb{R}. We have:

f(-1)=\sin (-1)+6-5=1-\sin 1&gt;0,\quad f(0)=-5&lt;0

Then, 0\in (f(0),f(-1)) and according to the Intermediate Value Theorem there exists a\in (-1,0) such that f(a)=0 or equivalently \sin a=6a+5

(b) Now, denote g(x)=\ln x+x^2-3. Clearly, f in continuos in (0,+\infty). We have:

g(1)=-2&lt;0,\quad g(2)=\ln 2+1&gt;0

and we can reason as in (a).
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Is it possible to arrange six pencils such that each one touches the other five? If so, how? This is an adaption of a Martin Gardner puzzle only I changed it from cigarettes to pencils and left out the clues because PF folks don’t need clues. From the book “My Best Mathematical and Logic Puzzles”. Dover, 1994.
Thread 'Imaginary Pythagoras'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top