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dfang
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Homework Statement
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I know for t[u(t)-u(t-2)], we can simplify that to tu(t)-((t-2)+2)u(t-2) which then gives us tu(t)-(t-2)u(t-2)-u(t-2). Now, the laplace transform seems trivial but I am having problems with this equation:
sin(t)[u(t)-u(t-pi)]
Homework Equations
[/B]n/a
3. The Attempt at a Solution
sin(t)[u(t)-u(t-pi)]
=sin(t)u(t) - sin(t)u(t-pi)
= sin(t)u(t) - sin ((t-pi)+pi)u(t-pi)
Where do we go from here as the t-pi+pi is inside the sine i.e its a function of sine. We can't exactly take it out and multiply over. How can we take this to the form where I can take the laplace transform easily ?
Similar problem where I am having trouble: e-t u(t-2). This one I do not even know where to start as the -t is in the exponent this time. Thanks.
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