Laplace Transform of t u(t-2) using Basic Definition

In summary, to find the Laplace transform of g(t) = t u(t-2) using the basic definition, we can apply the t-shifting property or integrate from 2 to infinity. The inverse Laplace transform of 1 is not possible as it represents a constant function, which does not have a specific time domain representation.
  • #1
tommyhakinen
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Homework Statement


find the laplace transform of g(t) = t u(t-2) using the basic definition.


Homework Equations


L{f(t)} = ∫f(t)e-stdt from 0 to infinity

The Attempt at a Solution


I am able to get the transform by applying the t-shifting property. However, how do I do it by using basic definition? thanks.
 
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  • #2
tommyhakinen said:

Homework Statement


find the laplace transform of g(t) = t u(t-2) using the basic definition.


Homework Equations


L{f(t)} = ∫f(t)e-stdt from 0 to infinity

The Attempt at a Solution


I am able to get the transform by applying the t-shifting property. However, how do I do it by using basic definition? thanks.
By integrating! Since H(x) is defined to be 0 for x< 0, 1 for x>= 0, H(t-2)= 0 for t< 2, 1 for t<= 2.
[tex]L{f(t)}= \int_2^\infty t e^{-st}dt[/tex]
That should be easy.
 
  • #3
Thank you very much. One more question. what is the inverse laplace transform of 1? Is it possible to get it? if there is, what can be done? thanks..
 

FAQ: Laplace Transform of t u(t-2) using Basic Definition

What is the Laplace Transform?

The Laplace Transform is a mathematical tool used in engineering and physics to solve differential equations. It transforms a function from the time domain to the complex frequency domain, making it easier to solve certain types of problems.

What types of problems can be solved using the Laplace Transform?

The Laplace Transform is commonly used to solve initial value problems, boundary value problems, and differential equations in engineering and physics. It can also be used to solve problems involving linear systems and circuits.

How do you perform a Laplace Transform?

The Laplace Transform of a function f(t) is denoted as F(s) and is calculated using the integral: F(s) = ∫0 f(t)e-stdt, where s is a complex variable. This integral can be solved using tables or software such as Mathematica.

What are the advantages of using the Laplace Transform?

The Laplace Transform allows for the solution of complex differential equations, which may not be solvable using traditional methods. It also simplifies calculations and makes it easier to solve problems involving functions with discontinuities or singularities.

Are there any limitations to using the Laplace Transform?

The Laplace Transform is limited to solving linear problems and may not be applicable to non-linear systems. It also requires knowledge of complex variable analysis and may not be suitable for beginners. Additionally, the inverse Laplace Transform may not have a closed-form solution, making it difficult to find the original function.

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