Laplace Transform: Order of transformation

In summary, a Laplace transform is a mathematical operation used in engineering and physics to convert a function of time into a function of complex frequency. The order of transformation in Laplace transform refers to the highest power of the variable s in the transformed function and can range from 0 to infinity. It is determined by looking at the highest power of s in the transformed function and is important in determining the type of function obtained after the transformation. The order must be a non-negative integer and cannot be negative, as it represents the number of derivatives in the original function.
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Homework Statement


Find the Laplace transform for [tex]\[t\left( {\int\limits_0^{t - a} {f(u)du} } \right)H(t - a)\][/tex] proving the properties used.


Homework Equations



If f(t) transforms into F(s):

a) [tex]\[{( - t)^{n}f(t) \to {F^{(n)}}(s)\][/tex]

b) [tex]\[\int\limits_0^t {f(u)du} \to \frac{{F(s)}}{s}\][/tex]

c) [tex]\[f(t - a)H(t - a) \to {e^{ - as}}F(s)\][/tex]

The Attempt at a Solution



Here's my question: in what order should I use these properties? There's only one posibility for the translation, and that's that the transform is multiplied by e-as. But with the derivative of F(s) and the division for s there are two posibilities:

1) That the Laplace transform of [tex]\[t\left( {\int\limits_0^{t - a} {f(u)du} } \right)H(t - a)\][/tex] be [tex]\[\frac{{ - {e^{ - as}}{F^'}(s)}}{s}\][/tex].

2) That the Laplace transform be [tex]\[ - {e^{ - as}}{\left[ {\frac{{F(s)}}{s}} \right]^'}\][/tex].

What's the correct one and why? I couldn't find a reason to use either one but not the other.

EDIT: In property a), the lineal variable t should have an exponent without brackets, since it's not the n-th derivative but the n-th power.
 
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The correct approach is to first use property c) to transform \[f(u)H(t-a)\] into \[e^{-as}F(s)\]. Then, use property b) to transform the integral \[\int_0^{t-a}e^{-as}F(s)ds\] into \[\frac{e^{-as}}{s}F(s)\]. Finally, use property a) to transform the t in front of the integral into \[\frac{d}{ds}\left(\frac{e^{-as}}{s}F(s)\right)\]. This will give you the Laplace transform of \[t\left(\int_0^{t-a}f(u)du\right)H(t-a)\] as \[\frac{d}{ds}\left(\frac{e^{-as}}{s}F(s)\right)\].

The reason why we use property b) first and then property a) is because the integral \[\int_0^{t-a}f(u)du\] is inside the function t, so we need to transform it first before we can use property a). And the reason why we use property c) is because the function \[f(u)H(t-a)\] has a shifted argument, so we need to use the property that deals with shifted arguments first.

In general, when using Laplace transforms, it is important to pay attention to the order in which the properties are used. This will help ensure that the correct transformation is obtained.
 

FAQ: Laplace Transform: Order of transformation

What is a Laplace transform?

A Laplace transform is a mathematical operation that converts a function of time into a function of complex frequency. It is commonly used in engineering and physics to solve differential equations and analyze systems in the frequency domain.

What is the order of transformation in Laplace transform?

The order of transformation in Laplace transform refers to the highest power of the variable s in the transformed function. It is often denoted by the letter n and can range from 0 to infinity.

How do you find the order of transformation in a Laplace transform?

The order of transformation can be found by looking at the highest power of the variable s in the transformed function. If the function is written in the form of a polynomial in s, the highest power of s will be the order of transformation.

What is the significance of the order of transformation in Laplace transform?

The order of transformation in Laplace transform is important because it determines the type of function that will be obtained after the transformation. For example, a function with a higher order of transformation will result in a more complex function in the frequency domain.

Can the order of transformation in Laplace transform be negative?

No, the order of transformation in Laplace transform must be a non-negative integer. This is because it represents the number of derivatives in the original function, which cannot be negative. If the order is negative, the transformation cannot be performed.

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