Laplace Transform - Step Functions

In summary, to find the Laplace transform of the given function, first use the general formula f(t) = g(t)[u(t-a) - u(t-b)] to represent the function in terms of step functions. Then, apply the Laplace transform property for step functions to get the final result.
  • #1
LadyAnn
3
0

Homework Statement


Please help by explaining in detail how to find the Laplace transform of the function

f(t) = { 2 0 <= t < 3
{ -2 t >= 3.





Homework Equations





The Attempt at a Solution


For the most part I know that U(t-3)(t-3).

I want to account for the amplitude of 2 like this but I think that I am wrong.

2-2U(t-3)*-2(t-3). I feel that I'm on the right track but might have set up the problem incorrectly. if I have it set up correctly I think I can go from there but would like directional help please.

Thank You,

Lady Ann.
 
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  • #2
LadyAnn said:
2-2U(t-3)*-2(t-3)
No I don't think that is correct.

In general, if

[tex]f(t)= g(t) \ \mbox{for} \ a\leq t \leq b[/tex] and is zero everywhere else, then

[tex]f(t) = g(t)[u(t-a) - u(t-b)][/tex].
 

FAQ: Laplace Transform - Step Functions

What is the Laplace transform?

The Laplace transform is a mathematical operation that converts a function of time into a function of complex frequency. It is often used in physics and engineering to solve differential equations and analyze systems in the frequency domain.

What is a step function?

A step function is a mathematical function that changes from one constant value to another at a specific point. It is often represented graphically as a series of horizontal lines, with a sudden jump at the point of change.

How is the Laplace transform applied to step functions?

The Laplace transform of a step function can be calculated using the formula L{u(t-a)}=e^(-as)/s, where u(t-a) is the step function with a step at time a. This formula is derived from the definition of the Laplace transform and can be used to solve problems involving step functions.

What are the advantages of using Laplace transform to analyze step functions?

The Laplace transform allows us to solve differential equations involving step functions in the frequency domain, which can often be simpler and more intuitive than solving them in the time domain. It also allows for the use of complex numbers, which can provide more information about the behavior of a system.

Are there any limitations to using Laplace transform with step functions?

One limitation of using Laplace transform with step functions is that it assumes the function is zero for negative time values. This means that it cannot be used for systems that have non-zero initial conditions. Additionally, the inverse Laplace transform can be difficult to calculate for some functions, making it challenging to find the original time-domain function.

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