Last edited by a moderator: May 3, 2017

  • Thread starter kittymaniac84
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In summary, the conversation discusses a second order reaction with a rate constant of 0.169 L/(mol s). The initial concentration of A is 0.159 mol/L and the desired final concentration is 6.07 x 10^-3 mol/L. The equation needed for a 2nd order reaction is aA = products, and the relevant values for solving the problem are the initial and final concentrations.
  • #1
kittymaniac84
17
0
A reaction of the form aA = products is second order with a rate constant of 0.169
L/(mol s). If the initial concentration of A is 0.159 mol/L, how many seconds would it
take for the concentration of A to decrease to 6.07 x 10^-3 mol/L ?

how to solve these
 
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  • #2
do your own hw
 
  • #3
If your not going to help, don't bother to post any rude comments. That is not how you help someone learn.
 
  • #4
kittymaniac84 said:
If your not going to help, don't bother to post any rude comments. That is not how you help someone learn.

NO that is what the HOMEWORK forum is for. And no one is going to help you there either because you haven't even shown that you have tried any work on your own.
 
  • #5
I don't know how to attempt this. I will find other places who can help.
 
  • #6
gravenewworld said:
do your own hw
Ok jackass. Next time, just refer them to the Forum rules.

FAQ: Why hasn't anybody answered my question? - https://www.physicsforums.com/showthread.php?t=94384

Anyways Kitty ...

1) What is the equation you will need for a 2nd order reaction?
2) What values do you have? Initial/Final concentration ... etc?

Refer to the image for equations:

http://alt1.mathlinks.ro/Forum/latexrender/pictures/1/b/a/1bacaba62a260d46b7600cc644b6bba500f54b3b.gif
 
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