- #1
amygoogs
- 1
- 0
I have a long equation with square roots that need to be continued on the next line. Can you tell me how to split it up but continue the square root on the next line:
\begin{equation}
betaone=\dfrac{-2a(betaminusbeta)}{\alpha}-\frac{8a(betaminusbeta)^2}{3\alpha^2} \sqrt[3]{\tfrac{1}{2}\left[\frac{27\alpha^3}{32(betaminusbeta)^2} \left( \frac{1}{betaminusbeta} - \frac{1}{a}ccc \right) \right] + \sqrt{\left(\frac{9\alpha^2}{16(betaminusbeta)^2} \right)^2 -4\left(\frac{9\alpha^2}{3}^2-3ac \right)^3} }
\end{equation}
ccc and betaminusbeta are expressions that I've specified up in the header, I took them out so it'd be easier for you guys to comment on this part.
\begin{equation}
betaone=\dfrac{-2a(betaminusbeta)}{\alpha}-\frac{8a(betaminusbeta)^2}{3\alpha^2} \sqrt[3]{\tfrac{1}{2}\left[\frac{27\alpha^3}{32(betaminusbeta)^2} \left( \frac{1}{betaminusbeta} - \frac{1}{a}ccc \right) \right] + \sqrt{\left(\frac{9\alpha^2}{16(betaminusbeta)^2} \right)^2 -4\left(\frac{9\alpha^2}{3}^2-3ac \right)^3} }
\end{equation}
ccc and betaminusbeta are expressions that I've specified up in the header, I took them out so it'd be easier for you guys to comment on this part.