- #1
isaaclimdc
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How does the amount of lead sulfate on the electrodes of a lead-acid battery affect its electric potential?
The discharge reaction of a lead-acid battery produces amorphous lead (II) sulfate at the electrodes. If I can work out the number of moles of lead sulfate formed, how can I interpret this in terms of electric potential? (i.e. more PbSO4, greater potential?
What about qualitatively and quantitatively?
Also, why does the distance between the electrodes of a battery affect its electric potential?
Can this be explained in terms of chemistry? I know it is because of the internal resistance of the cell, but that is more of a physics-related explanation (Ohm's Law)
Any help is much appreciated,
Isaac
The discharge reaction of a lead-acid battery produces amorphous lead (II) sulfate at the electrodes. If I can work out the number of moles of lead sulfate formed, how can I interpret this in terms of electric potential? (i.e. more PbSO4, greater potential?
What about qualitatively and quantitatively?
Also, why does the distance between the electrodes of a battery affect its electric potential?
Can this be explained in terms of chemistry? I know it is because of the internal resistance of the cell, but that is more of a physics-related explanation (Ohm's Law)
Any help is much appreciated,
Isaac