Left Invariant Metric: What I Don't Understand

  • #1
ergospherical
1,073
1,367
I haven't learned about Lie Groups yet, but came across this question.

1626811932297.png


What I don't understand:
- is the semi-direct product ##R_+ \ltimes R^4## here a matrix group with elements ##\begin{pmatrix} \lambda & x^{\mu} \\ 0 & 1 \end{pmatrix}##? And is the group multiplication then matrix multiplication?
- I guessed that because ##R_+ \ltimes R^4 \sim R^5## that the metric acts on matrices ##g_1, g_2## in the group as it would acting on two vectors in ##R^5##, but what does it mean that the metric is left invariant? Is it that for an arbitrary matrix ##g_3## in the group that ##\langle g_1, g_2 \rangle = \langle g_3 g_1, g_3 g_2 \rangle##?

(Not sure if any of that's right and maybe it'd be better to actually learn the theory first, but sometimes a practical example can't hurt?)
 
  • Like
Likes Delta2 and Dale
Physics news on Phys.org
  • #2
@fresh_42 do you have any words of wisdom? 😜
 
  • #3
At first glance, I think this is the subgroup of the Poincaré group with all 4 translations, but only one dilatation (multiplication with ##M_{\mu\nu}=\lambda ##) as opposed to the entire Lorentz group. You could basically do all the things you do with the Poincaré group, but with far fewer multiplications, since the entire Lorentz subgroup is reduced to ##\mathbb{R}_+.##
 
  • Like
Likes ergospherical

Similar threads

Replies
13
Views
2K
Replies
5
Views
882
Replies
8
Views
430
Replies
144
Views
8K
Replies
10
Views
1K
Replies
8
Views
4K
Back
Top