Lens Refraction Problems: Help with Calculating Image Distance and Magnification

  • Thread starter moonlit
  • Start date
  • Tags
    Refraction
In summary, the conversation discusses three problems involving converging and diverging lenses and the use of the lens equation to determine image distance and height, as well as magnification. The first problem involves a 14-cm-tall object located 121 cm in front of a lens with a focal length of 85 cm. The second problem deals with an object located 38.2 cm from a lens with a focal length of 59.2 cm. The third problem requires finding the distance at which an object should be placed in front of a diverging lens with a focal length of -14 cm in order to reduce the size of its image by a factor of 2.1. The conversation ends with the individual figuring out the solutions
  • #1
moonlit
57
0
I'm really not sure how to figure these 3 problems out. Can someone please help me. Thanks.

1) A converging lens has a focal length of 85 cm. A 14-cm-tall object is located 121 cm in front of this lens. (a) What is the image distance? (b) What is the image height? Be sure to include the proper algebraic sign.

2) An object is located 38.2 cm to the left of a converging lens whose focal length is 59.2 cm. (a) Determine the image distance and (b) the magnification.

3) An object is 27 cm in front of a diverging lens that has a focal length of -14 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 2.1?
 
Physics news on Phys.org
  • #3
I got the last one but the other two I'm still unsure of...
 
  • #4
If you would like some help, show your work and I'll take a look.
 
  • #5
Nevermind, I figured it out. Thanks anyway!
 

Similar threads

Replies
2
Views
513
Replies
5
Views
756
Replies
3
Views
781
Replies
1
Views
2K
Replies
4
Views
4K
Replies
3
Views
2K
Back
Top