- #1
Argonaut
- 45
- 24
- Homework Statement
- Prove that
$$\lim_{x\to\infty} \frac{e^x}{x^n}=\infty$$
for any positive integer n. This shows that the exponential function approaches infinity faster than any power of x.
[Stewart Calculus, 4.4.73]
- Relevant Equations
- Derivative of Exponential Functions
Power Rule
L'Hospital's Rule
Mathematical Induction
The Student's Manual simply applies l'Hospital's Rule n-times to arrive at ##\frac{e^x}{n!}\to\infty## as ##x\to\infty##.
However, I'm wondering if I could use Mathematical Induction to prove this. Is the following correct and sufficiently rigorous (at least for an undergraduate-level Calculus 1 course)?
Show that the statement is true for n=1:
We apply l'Hospital's Rule.
$$\lim_{x\to\infty} \frac{e^x}{x^1}=\lim_{x\to\infty} e^x = \infty$$
Show that the statement is true for n+1 if it is true for n:
Assume ##\lim_{x\to\infty} \frac{e^x}{x^n}=\infty##. Then by applying l'Hospital's Rule to case n+1, we have
$$
\lim_{x\to\infty} \frac{e^x}{x^{n+1}}=
\lim_{x\to\infty} \frac{e^x}{(n+1)x^{n}}=
\frac{1}{n+1}\lim_{x\to\infty} \frac{e^x}{x^{n}}=\infty
$$
Therefore, the statement has been proven true for all positive integers n by the principle of Mathematical Induction.
However, I'm wondering if I could use Mathematical Induction to prove this. Is the following correct and sufficiently rigorous (at least for an undergraduate-level Calculus 1 course)?
Show that the statement is true for n=1:
We apply l'Hospital's Rule.
$$\lim_{x\to\infty} \frac{e^x}{x^1}=\lim_{x\to\infty} e^x = \infty$$
Show that the statement is true for n+1 if it is true for n:
Assume ##\lim_{x\to\infty} \frac{e^x}{x^n}=\infty##. Then by applying l'Hospital's Rule to case n+1, we have
$$
\lim_{x\to\infty} \frac{e^x}{x^{n+1}}=
\lim_{x\to\infty} \frac{e^x}{(n+1)x^{n}}=
\frac{1}{n+1}\lim_{x\to\infty} \frac{e^x}{x^{n}}=\infty
$$
Therefore, the statement has been proven true for all positive integers n by the principle of Mathematical Induction.