Light Intensity transmitted through the polarized and analyzer

[superman2287]

Homework Statement

Here is the question:Unpolarized light of intesity Io is incident on a polarizer-analyzer pair. If the angle between the polarizer and analyzer is 21°, what light intensity is transmitted through the polarizer and analyzer respectively?
Your answers will be in terms of Io.

Tbh i just need to find out how to get the unpolarized light of intensity.

givens: angle measure = 21
So far...i don't know how to do this one.

Homework Equations

Equations: I=Iocos^2theta
1/2Io

The Attempt at a Solution

I don't have any attempts as i don't know what to do.

 

[anathema]

Thank you for your question. To find the transmitted light intensity through the polarizer and analyzer, we will need to use the Malus' law, which relates the intensity of polarized light to the angle between the polarizer and analyzer. The equation is as follows:

I = Io * cos^2(theta)

Where I is the transmitted light intensity, Io is the incident light intensity, and theta is the angle between the polarizer and analyzer.

In this case, the given angle is 21°, so we can plug that into the equation:

I = Io * cos^2(21°)

We can also use the fact that unpolarized light has equal amounts of light vibrating in all directions, so we can say that the initial intensity, Io, is equivalent to the average intensity of the polarized light, which is 1/2 of the maximum intensity.

Therefore, we can rewrite the equation as:

I = (1/2Io) * cos^2(21°)

This gives us the transmitted light intensity through the polarizer and analyzer.

I hope this helps you with your problem. Let me know if you have any further questions or concerns.