- #1
mhl2188
- 1
- 0
Hello, here is the problem i am having trouble with. The sun falls on a concave mirror and forms an image 3 cm from the mirror. If an object 24mm high is placed 12 cm from the mirror, where will its image be formed? So far, i have decided that since 1/f = 1/do + 1/di...
1/f = 1/do + 1/3 = 1/12 + 1/di
I also decided that hi/2.4 = -di/12... The problem is...even if i solve for di in terms of hi and plug that into my first equation i don't have enough information to solve for do. I am stuck and this problem is due tomorrow... please help
thanks
mhl
1/f = 1/do + 1/3 = 1/12 + 1/di
I also decided that hi/2.4 = -di/12... The problem is...even if i solve for di in terms of hi and plug that into my first equation i don't have enough information to solve for do. I am stuck and this problem is due tomorrow... please help
thanks
mhl