Lim x approaches -3 of (x^2+6x+9)/(x-3)

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In summary, the limit of the given expression as x approaches -3 is 0. This is because both the numerator and denominator are continuous at x = -3 and the denominator is not equal to 0 at that point. Therefore, the limit exists and is equal to 0.
  • #1
kendalgenevieve
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Determine the limit, if it exists. If not, explain why it does not exist.

lim x approaches -3 of (x^2+6x+9)/(x-3)
 
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  • #2
kendalgenevieve said:
Determine the limit, if it exists. If not, explain why it does not exist.

lim x approaches -3 of (x^2+6x+9)/(x-3)

The top and bottom are both continuous at x = -3 and the denominator isn't 0 there, so what do you think the limit is?
 
  • #3
Prove It said:
The top and bottom are both continuous at x = -3 and the denominator isn't 0 there, so what do you think the limit is?

When I solved it I got a 0/-6 so would the limit be just zero?
 
  • #4
kendalgenevieve said:
When I solved it I got a 0/-6 so would the limit be just zero?

Yes, when the expression evaluates to a finite value, then that is the value of the limit. :)
 

FAQ: Lim x approaches -3 of (x^2+6x+9)/(x-3)

What are limits in mathematics?

Limits are a fundamental concept in mathematics that describes the behavior of a function as the input approaches a certain value. It is a way to measure the value of a function at a specific point, even if that point is not included in the function's domain.

How do limits help in solving mathematical problems?

Limits help in solving mathematical problems by providing a way to evaluate a function at a certain point, even if it is not defined at that point. They also help in understanding the behavior of a function and making predictions about its values.

What is the limit notation used in mathematics?

The limit notation used in mathematics is "lim" with the input variable approaching a certain value placed in parentheses after the function. For example, "lim x → a" represents the limit of a function as x approaches the value of a.

Can limits be used to find the value of a function at a point?

Yes, limits can be used to find the value of a function at a point, as long as the function is continuous at that point. The limit will give the same value as the function's value at that point.

Are there any special rules for evaluating limits?

Yes, there are special rules for evaluating limits, such as the sum, difference, and product rule, as well as the power rule and the quotient rule. These rules can make solving limits easier and more efficient.

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