- #1
tomtom690
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Homework Statement
Hello, I don't entirely understand the question here. It is the limit of a sequence, however it is defined on what appears to be an interval, and is different if n is odd or even. Excuse the messy notation here, I don't know how to use LaTeX.
Let the sequence {A_n : n>=1} subset of P(Omega) be defined by:
A_n={( (n^2-1)/3n^3+1 , 4n^2/n^2+1 ] n even
{( 5n^2/(2n^2-3) , (7n^2+5)/3n^2 ] n odd
Study if lim A_n, n-->infinity exists.
In words, the n even case is "the interval open on the left and closed on the right from n squared minus one over three n cubed plus one, to four n squared over n squared plus one."
Its the interval bit which doesn't make any sense to me!
Homework Equations
This is part of an advanced probability course (hence the P(Omega)) if this means anything.
The Attempt at a Solution
Well, first I tried evaluating limits as n goes to infinity on all four expressions, hoping that I would get numbers which would be the same in the odd and even case. I used l'hopitals rule in all cases, and for the evens got an interval of (1/3, 4] and the odds of (5/2, 7/3] which is rediculous, for starters!
Thanks in advance