Limit of x^n+y^n as n -> ∞: max(x, y)

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In summary, the limit for n->infinity of the nth root of (x^n+y^n) is equal to the maximum of x and y. This can be shown by taking x outside the nth root, using the binomial theorem, and showing that the limit of the nth root is 1. This holds true for both cases where x>y and y>x.
  • #1
raphael3d
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show for two positive numbers x,y>0 that

limit for n->infinity : [tex]\sqrt[n]{x^n+y^n}[/tex] = max {x,y}

i don't know how to make a upper boundary(lower boundary is >0 i suppose)
something like assume for instance x bigger than y and than make a boundary with it, but how?
 
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  • #2
Assume x>y, take x outside the nth root. Use binomial theorem to show the limit of the nth root is 1.
 
  • #3
x^n = (x^n+y^n) = x^n(1+(y^n)/(x^n))

=>

nth root of (x^n+y^n)=x*nth root of (1+(y^n)/(x^n)), and for x>y, =>x. the same applies for the opposite case.
 

FAQ: Limit of x^n+y^n as n -> ∞: max(x, y)

What is the limit of x^n+y^n as n approaches infinity?

The limit of x^n+y^n as n approaches infinity is equal to the maximum value between x and y. This means that if x is greater than y, the limit will be equal to x, and if y is greater than x, the limit will be equal to y.

How does the limit of x^n+y^n change as n approaches infinity?

As n approaches infinity, the limit of x^n+y^n will either approach the value of x or the value of y, depending on which one is greater. This means that the limit will not actually reach infinity, but rather approach the maximum value between x and y.

Can the limit of x^n+y^n be calculated without knowing the values of x and y?

No, the limit of x^n+y^n cannot be calculated without knowing the values of x and y. The limit is dependent on the values of x and y, and will vary depending on which one is greater.

How does the limit of x^n+y^n as n approaches infinity relate to the graph of x^n+y^n?

The limit of x^n+y^n as n approaches infinity is equal to the maximum value between x and y. This is also the highest point on the graph of x^n+y^n, as n approaches infinity. Therefore, the limit can be seen as the maximum value or peak of the graph.

Can the limit of x^n+y^n ever be negative?

Yes, the limit of x^n+y^n can be negative if both x and y are negative. In this case, the limit will be equal to the maximum negative value between x and y. If either x or y is positive, the limit will be positive or zero.

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