- #1
Sirsh
- 267
- 10
Homework Statement
The position vector of a particle is given in the terms of t, by,
s = (e-t+3*cos(2t)i+2tj+(e-t+3*sin(2t)k)
Find the limiting value of speed when t approaches positive infinity. The answer says "s = ..."
The Attempt at a Solution
I have evaluated the limits of all the components of this vector function individually:
e-t = 0
3*cos(2t) = -3 to 3
2t = positive infinity
3*sin(2t) = -3 to 3.
I know that the magnitude of the velocity vector is equal to the speed of the particle, so I'm not sure if i should have done the limits on the velocity vector that i found by differentiating the position vector? but the answer is in the form of "s = ..."
Any help would be appreciated, Thanks!