Line Integral dl in spherical polar coordinates

In summary, we are trying to evaluate a line integral of Vector A dot dL, where A is given as a function of r, theta and fi in spherical polar coordinates. The closed curve C is a circle parametrised by fi at arbitrary values of (r, theta), and the line element dl can be rewritten in terms of spherical polar coordinates. The limits of the line integral depend on the chosen closed curve, and in this case, they would be from 0 to 2π.
  • #1
wam_mi
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1

Homework Statement



Hi guys,

I'm trying to evaluate a line integral, Integration of Vector A dot dL

The vector A was given to be a function of r, theta and fi in spherical polar coordinates.

The question states that an arbitrary closed loop C is the circle parametrised by fi at some arbitrary values of (r, theta).

I would like to ask the following questions:

(i) How do I rewrite dl, the line element, in terms of spherical polar co-ordinates? What does it mean by the closed curve C is the circle parametrised by fi at some arbitrary values of (r, theta). How does it change my dl if C wasn't a circle?

(ii) What are the limits of the line integral?



Thanks guys!



Homework Equations





The Attempt at a Solution

 
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  • #2
(i) dl in terms of spherical polar coordinates can be written as:dl = (r sin(θ) cos(φ))dφ + (r sin(θ) sin(φ))dθ + (r cos(θ))drThe closed curve C being parametrised by fi at some arbitrary values of (r, theta) means that the line integral is taken over a circle in spherical polar coordinates, with a radius of r, an elevation of θ and azimuth of φ. If C wasn't a circle, the form of dl would still be the same, but the limits of the line integral would change accordingly.(ii) The limits of the line integral depend on the closed curve C chosen. Since C is a circle, the limits are given by the start and end points of the path. In this case, the limits of the line integral would be from 0 to 2π.
 

FAQ: Line Integral dl in spherical polar coordinates

What is a line integral dl in spherical polar coordinates?

A line integral dl in spherical polar coordinates is a type of mathematical calculation used to measure the value of a vector field along a curve in three-dimensional space. It takes into account both the direction and magnitude of the vector field at each point along the curve.

How is a line integral dl in spherical polar coordinates different from other types of line integrals?

The main difference is that spherical polar coordinates use a different coordinate system than other types of line integrals, such as Cartesian coordinates. Spherical polar coordinates use a radius (r), an azimuthal angle (θ), and a polar angle (φ) to define points in three-dimensional space, while Cartesian coordinates use x, y, and z coordinates.

What is the formula for calculating a line integral dl in spherical polar coordinates?

The formula for a line integral dl in spherical polar coordinates is ∫C F(r,θ,φ) dl = ∫a^b F(r(t),θ(t),φ(t)) |r'(t)| dt, where F is the vector field, r is the position vector, t is the parameter representing points on the curve, and a and b are the initial and final values of t.

What are some real-world applications of line integral dl in spherical polar coordinates?

Line integral dl in spherical polar coordinates has many practical applications in physics and engineering, such as calculating the work done by a force on a particle moving along a curved path, finding the flux of a vector field through a surface, and determining the charge enclosed by a closed surface in an electric field.

What are some common challenges when working with line integral dl in spherical polar coordinates?

Some common challenges include understanding and visualizing the spherical polar coordinate system, converting between spherical polar and Cartesian coordinates, and setting up the appropriate limits of integration for a given curve and vector field. Additionally, the complexity of the calculations involved in line integral dl in spherical polar coordinates can also be challenging for some individuals.

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