Line Parallel to the Plane Equation (Final Exam Review)

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The line represented by <x,y,z> = <3,1,4> + t<4,-5,2> is parallel to the plane defined by the equation 2x + 2y + z = 7 because its direction vector (4,-5,2) is perpendicular to the plane's normal vector derived from the plane equation. The dot product of the direction vector and the normal vector equals zero, confirming their perpendicularity. This relationship indicates that the line does not intersect the plane, thus maintaining parallelism. Understanding the geometric relationship between lines and planes is crucial for solving such problems. This confirms that the line is indeed parallel to the specified plane.
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Homework Statement


Explain why the line <x,y,z> = <3,1,4> + t<4,-5,2> is parallel to the plane with equation 2x + 2y +z = 7


Homework Equations


The normal vector of <x,y,z> [4,-5,2] and the plane equation 2x + 2y + z = 7


The Attempt at a Solution


Well, I'm trying to review for the final exam and I'm missing a crucial notes sheet.

So, I attempted to do the dot product of the normal vector and the plane equation vector which is:

4*2 + -5*2 + 1*2 = 0

However, that didn't add up to 7 which would mean == lines.

Though, I think by writing out the dot product I technically proved perpendicularity since plane equations are based off a vector and a point. Thus, making it perpendicular to that point.

So if two bits are perpendicular to the same point then they are parallel to each other.

Any help, would be much appreciated.
 
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Yes, that's correct. If the line <x,y,z> = <3,1,4> + t<4,-5,2> is parallel to the plane, then its direction vector i.e. (4,-5,2) is perpendicular to the plane's normal vector.
 
Thank You So Much!
 

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