- #1
stunner5000pt
- 1,465
- 4
Show taht [itex] {a + bx + cx^2, a_{1} + b_{1} x + c_{1} x^2, a_{2} + b_{2} x + c_{2} x^2} [/itex] is a basis of P2 iff {(a,b,c) , (a1,b1,c1) , (a2,b2,c2)} is a basis of R3
suppose [itex] {a + bx + cx^2, a_{1} + b_{1} x + c_{1} x^2, a_{2} + b_{2} x + c_{2} x^2} [/itex] is a basis of P2 then
a linear combination of those three vectors would require all teh scalar multipliers to be zeros
but I am not sure where to go from there... do i have to somehow write he basis of P2 as a basis of R3??
DOes the same apply for the only if part?
Determien whether the transformation has an iverse and if so then find the action of its inverse
T; R4 - > R4
T(x,y,z,t) = (x+y,y+z,z+t,t+x)
Both the preimage and the image have the same dimension i have to show that either t is onto or one to one
how owuld i show it is onto? Or one to one?? Do i simply line up x1s and y1s and see if they are equal if the image of them is equal??
suppose [itex] {a + bx + cx^2, a_{1} + b_{1} x + c_{1} x^2, a_{2} + b_{2} x + c_{2} x^2} [/itex] is a basis of P2 then
a linear combination of those three vectors would require all teh scalar multipliers to be zeros
but I am not sure where to go from there... do i have to somehow write he basis of P2 as a basis of R3??
DOes the same apply for the only if part?
Determien whether the transformation has an iverse and if so then find the action of its inverse
T; R4 - > R4
T(x,y,z,t) = (x+y,y+z,z+t,t+x)
Both the preimage and the image have the same dimension i have to show that either t is onto or one to one
how owuld i show it is onto? Or one to one?? Do i simply line up x1s and y1s and see if they are equal if the image of them is equal??
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