Linear algebra question, quadratic forms.

In summary, the conversation discusses the possibility of a unique solution for the equation xAx=b, given that A, x, and b are all stochastic vectors/matrices. It is concluded that there can be multiple solutions and examples are provided to demonstrate this.
  • #1
enfield
21
0
A is a square matrix. x, b are vectors.

I know for Ax=b, that given b, there are an infinite number of pairs (A, x) which satisfy the equation.

I'm wondering if the same is true for xAx=b.

in particular, what if (x, A, b) are all stochastic vectors/matrices (i.e the entries of b and x add to 1, and so do each column of A). Would that make it so there was a single solution (A,x) for a given b?

Thanks.
 
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  • #2
First, b cannot be a vector: [itex]xAx[/itex] will be a number, not a vector. And it is easy to find examples showing there is not a unique solution: Let b= 1. Then
[tex]\begin{pmatrix}1 & 0\end{pmatrix}\begin{pmatrix}1 & 0 \\ 0 & 0 \end{pmatrix}\begin{pmatrix}1\\ 0\end{pmatrix}= 1[/tex]

Or
[tex]\begin{pmatrix}1 & 1\end{pmatrix}\begin{pmatrix}0 & 1 \\ 0 & 0 \end{pmatrix}\begin{pmatrix}1\\ 1\end{pmatrix}= 1[/tex]
 

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