Linear Algebra - Solving AC RLC circuit

In summary: If you look at the references above, you can figure out how to set up circuits with resistors, inductors, and capacitors. The resistance matrix can be found by solving the equations for each element in the circuit.
  • #1
YoshiMoshi
236
10

Homework Statement



So yeah I'm doing a project were I get to create a problem. I would like to learn how to solve a AC RLC circuit using linear algebra. I'm trying to find all of the currents on the edges of the graphs and find all of the voltages at the nodes connecting the edges. I don't think I should really put this in the engineering forum because I seem to really be struggling with the linear algebra and mathematics behind it. I solved circuits like this before, but not with the linear algebra perspective. If you can provide any assistance or point me in the right direction that would help. I'm just using all symbols for now and will put in numerical values later.

This is my weighted graph
IMG_20160408_010952662.jpg


Homework Equations

The Attempt at a Solution



Alright so I start with finding the incidence matrix.

equation_1.png


So then I find the impedance matrix

equation_2.png


Then I find the voltage and current source vectors.

equation_3.png


Than through this equation

equation_4.png


Than I can solve for the currents on each edge of the weight graph and find the nodal voltages of the weight graph

equation_5.png


So at this point I would just plug this into MATLAB once I assign numerical values.

Does this look ok so far?
 
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  • #2
BUMP went onto second page no answer.
 
  • #3
YoshiMoshi said:
BUMP went onto second page no answer.
You say you are struggling with the linear algebra behind solving say a complicated electrical circuit.

Why did you develop such a monster problem if this is the case? This circuit is clearly too complex to solve by hand, which is why you plan to dump it into MATLAB.
Couldn't you find a simpler circuit to practice on, one which is DC rather than AC, and get your LA problems straightened out before you move on to something which is unlikely to be solved by hand?

Otherwise, dump your calculations into MATLAB and see what solutions you get. You can always check the results afterward and see if the solution obeys the various network laws.
 
  • #4
I was told that the incidence matrix has to be at least 6x6. It is possible to solve by hand a DC RLC circuit by hand through the method mentioned above? I thought it might get more difficult to solve the problem in DC? Because I wouldn't be able to lump together impedance to create the resistance matrix?

Each branch would have something like

V = i*R + (1/C) integral i(t) dt + L*(d[i(t)]/dt)

How do I go about forming the resistance matrix of the resistance in each branch when it's DC? I guess I'm struggling with that. That's why I thought initially AC would be easier. In my book they show forming the resistance matrix with nothing but a resistive circuit. I have to make it a bit more complex because it can't be so similar to home work problems. I thought AC would be easier because than I could easily create the resistance matrix.

I guess my question is how exactly do I go about finding the resistance matrix of the graph if it's a DC RLC circuit. Like in my picture it would just be a DC voltage instead of V and a DC current source of I.

Thanks for any help!

I practiced on a purely resistive DC circuit and understand those easy. But will loose points if it's to similar to home work so I wanted to expand upon it and make it more difficult by making it a RLC circuit.
 
  • #5
YoshiMoshi said:
I was told that the incidence matrix has to be at least 6x6.
Why? Who told you this?
It is possible to solve by hand a DC RLC circuit by hand through the method mentioned above? I thought it might get more difficult to solve the problem in DC? Because I wouldn't be able to lump together impedance to create the resistance matrix?

You can do a mesh analysis on a much simpler DC circuit with as few as two loops.

https://en.wikipedia.org/wiki/Mesh_analysis

http://www.allaboutcircuits.com/textbook/direct-current/chpt-10/mesh-current-method/
Each branch would have something like

V = i*R + (1/C) integral i(t) dt + L*(d[i(t)]/dt)

How do I go about forming the resistance matrix of the resistance in each branch when it's DC? I guess I'm struggling with that. That's why I thought initially AC would be easier. In my book they show forming the resistance matrix with nothing but a resistive circuit. I have to make it a bit more complex because it can't be so similar to home work problems. I thought AC would be easier because than I could easily create the resistance matrix.

If you look at the references above, you can figure out how to set up circuits with resistors, inductors, and capacitors.

The incidence matrix is not that complicated to setup; it just depends on how many different connections are made at each circuit element.
I guess my question is how exactly do I go about finding the resistance matrix of the graph if it's a DC RLC circuit. Like in my picture it would just be a DC voltage instead of V and a DC current source of I.

Thanks for any help!

I practiced on a purely resistive DC circuit and understand those easy. But will loose points if it's to similar to home work so I wanted to expand upon it and make it more difficult by making it a RLC circuit.

It's best to start out with simple circuits. Once you have these down, then you can move on to more complex circuits.

The two references above are just samples. You can Google "mesh analysis" and get many more hits.
 
  • #6
Yeah I have solved circuits before using mesh analysis. It's easy. But how do I tie in linear algebra into this system by mesh analysis? I'm not exactly sure. I wouldn't know how to find the resistance matrix for an RLC circuit because I can't simply lump together the resistance of an RLC unless it was impedances that I could lump together in a AC case.,

I think mesh analysis provides me with the left null space of the linear system.

My professor said so =(

But how do I go about finding the Resistance matrix specifically?
 
  • #7
See I try and solve a simpler problem but am unsure how to find the matrix R in a DC RLC circuit. In a purely resistive circuit the matrix R is simply a diagonal matrix with the resistances in a RLC circuit I'm unsure how to form R. In a AC case I would just lump the impedances. So I'm not sure how to find R specifically in a DC RLC circuit.

IMG_20160412_204938522_HDR.jpg


Thanks for any help!
 

FAQ: Linear Algebra - Solving AC RLC circuit

1.

What is a Linear Algebra - Solving AC RLC circuit?

A Linear Algebra - Solving AC RLC circuit is a mathematical method used to analyze and solve electrical circuits that contain resistors, inductors, and capacitors. This method uses linear algebra techniques to determine the voltage and current values in the circuit.

2.

What are the key components of a RLC circuit?

The key components of a RLC circuit are resistors, inductors, and capacitors. Resistors impede the flow of current in the circuit, while inductors store energy in the form of a magnetic field and capacitors store energy in the form of an electric field.

3.

How do you solve a RLC circuit using Linear Algebra?

To solve a RLC circuit using Linear Algebra, you must first represent the circuit using a system of linear equations. This involves writing equations for the voltage and current at each component in the circuit. Then, you can use matrix operations to solve the system of equations and find the values of voltage and current in the circuit.

4.

What are the applications of Linear Algebra - Solving AC RLC circuits?

Linear Algebra - Solving AC RLC circuits have various applications in electrical engineering, including designing and analyzing electronic circuits, such as filters, amplifiers, and oscillators. It is also used in the fields of telecommunications, power systems, and control systems.

5.

What are some limitations of using Linear Algebra - Solving AC RLC circuits?

One limitation of using Linear Algebra - Solving AC RLC circuits is that it assumes all components in the circuit are ideal, meaning there are no losses or non-ideal behavior. In reality, components can have imperfections that may affect the accuracy of the calculations. Additionally, this method may become more complex and time-consuming for circuits with a large number of components.

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