- #1
theshonen8899
- 10
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This is for my Linear Algebra class:
For an angle θ ∈ [0, 2π), find the linear map fθ : R2 → R2, which describes the rotation
by the angle θ in the counterclockwise direction.
Hint : For a given angle θ, find a, b, c, d ∈ R such that fθ(x1, x2) = (ax1+bx2, cx1+dx2).
e^(x+yi) = (e^x)*(cos(y) + sin(y)i)
Circle in counterclockwise direction is (cosθ, sinθ)
therefore
cosθ = ax1 + bx2
sinθ = cx1 + dx2
i(sinθ = cx1 + dx2) = isinθ = icx1 + idx2
cosθ + isinθ = ax1 + bx2 + icx1 + idx2 = e^(0 + iθ) = e^(iθ)
This isn't much but I've really been working on this problem the entire day and I really have no clue what I'm supposed to do. I feel like a damned fool for having to resort to this but I'd really like to have a solution to this before I head off to my quiz.
Thanks guys.
Homework Statement
For an angle θ ∈ [0, 2π), find the linear map fθ : R2 → R2, which describes the rotation
by the angle θ in the counterclockwise direction.
Hint : For a given angle θ, find a, b, c, d ∈ R such that fθ(x1, x2) = (ax1+bx2, cx1+dx2).
Homework Equations
e^(x+yi) = (e^x)*(cos(y) + sin(y)i)
The Attempt at a Solution
Circle in counterclockwise direction is (cosθ, sinθ)
therefore
cosθ = ax1 + bx2
sinθ = cx1 + dx2
i(sinθ = cx1 + dx2) = isinθ = icx1 + idx2
cosθ + isinθ = ax1 + bx2 + icx1 + idx2 = e^(0 + iθ) = e^(iθ)
This isn't much but I've really been working on this problem the entire day and I really have no clue what I'm supposed to do. I feel like a damned fool for having to resort to this but I'd really like to have a solution to this before I head off to my quiz.
Thanks guys.