- #1
alingy1
- 325
- 0
Let $$A(2,-1,1)$$, $$B$$ and $$C$$ be the vertices of a triangle where $$\overrightarrow{AB}$$ is parallel to $$\vec{v}=(2,0,-1), $$$$\overrightarrow{BC}$$ is parallel to $$\vec{w}=(1,-1,1)$$ and $$\angle(BAC)=90°$$. Find the equation of the line through $$\(A\)$$ and $$\(C\)$$ in vector and parametric forms.
Well, there is not much I can do here. I could find the equation of the plane:
$$-x-3y-2z=-1$$ by finding the normal of the two vectors given.
Well, there is not much I can do here. I could find the equation of the plane:
$$-x-3y-2z=-1$$ by finding the normal of the two vectors given.