- #1
alexngo
- 4
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If two non-zero geometric vectors are parallel then they are linearly dependent.
For all n x n matrices A,B and C, we have (A - B)C = CA - CB
Let V be a vector space. If S is a set of linearly independent vectors in V such that S spans V,then S is a basis for V.
For all n x n matrices A and B, we have det (A + B) = det (A) + det (B)
If A is a matrix with det(A) = 0, then there are no solution to the equation Ax = b for any column vector b where b is not equal to 0
Row operations on an n x n matrix A have no effect on the determinant of A
For all n x n matrices A, we have det(A^t) = det(A)
For all n x n matrices A,B and C, we have (A - B)C = CA - CB
Let V be a vector space. If S is a set of linearly independent vectors in V such that S spans V,then S is a basis for V.
For all n x n matrices A and B, we have det (A + B) = det (A) + det (B)
If A is a matrix with det(A) = 0, then there are no solution to the equation Ax = b for any column vector b where b is not equal to 0
Row operations on an n x n matrix A have no effect on the determinant of A
For all n x n matrices A, we have det(A^t) = det(A)