- #1
sihag
- 29
- 0
Let T be a linear operator on a finite dimensional vector space V, over the field F.
Suppose TU = I, where U is another linear operator on V, and I is the Identity operator.
It can ofcourse be shown that T is invertible and the invese of T is nothing but U itself.
What I want to know is an example explicitly to show that the above is false if V is not finite dimensional.
Thank You.
Suppose TU = I, where U is another linear operator on V, and I is the Identity operator.
It can ofcourse be shown that T is invertible and the invese of T is nothing but U itself.
What I want to know is an example explicitly to show that the above is false if V is not finite dimensional.
Thank You.