- #1
Pietjuh
- 76
- 0
I've got a problem where I'm not sure my solution is true!
I have to proof that given the vacuum einstein's equation and the lorenz gauge condition imply that the stress energy tensor that generates the gravitational waves must have a vanishing divergence.
The vacuum einstein's equation is given by [tex]-\partial_{\alpha}\partial^{\alpha}\bar{h}^{\mu\nu} = 16\pi T^{\mu\nu}[/tex], and the lorentz condition is given by [tex]\partial^{\nu}\bar{h}_{\mu\nu} = 0[/tex]
Now if I just take the divergence to [itex]\nu[/tex] of this equation I obtain
[tex]-\partial_{\nu}\partial_{\alpha}\partial^{\alpha}\bar{h}^{\mu\nu} = 16\pi \partial_{\nu}T^{\mu\nu}[/tex]
Since we can swap the order of partial differentiation this becomes:
[tex]-\partial_{\alpha}\partial^{\alpha}\left(\partial_{\nu}\bar{h}^{\mu\nu}\right)= 16\pi \partial_{\nu}T^{\mu\nu}[/tex]
Now what I want to proof is that [tex]\partial_{\nu}\bar{h}^{\mu\nu} = \partial^{\nu}\bar{h}_{\mu\nu}[/tex]
I think that is true because [tex]\partial_{\gamma}\bar{h}^{\mu\nu} = - \partial^{\gamma}\bar{h}_{\mu\nu}[/tex]. So if I just replace [itex]\gamma[/itex] by [itex]\nu[/itex] this should imply that the divergence of T vanishes.
But I don't know for sure if I could just replace [itex]\gamma[/itex] by [itex]\nu[/itex]!
Thanks in advance!
I have to proof that given the vacuum einstein's equation and the lorenz gauge condition imply that the stress energy tensor that generates the gravitational waves must have a vanishing divergence.
The vacuum einstein's equation is given by [tex]-\partial_{\alpha}\partial^{\alpha}\bar{h}^{\mu\nu} = 16\pi T^{\mu\nu}[/tex], and the lorentz condition is given by [tex]\partial^{\nu}\bar{h}_{\mu\nu} = 0[/tex]
Now if I just take the divergence to [itex]\nu[/tex] of this equation I obtain
[tex]-\partial_{\nu}\partial_{\alpha}\partial^{\alpha}\bar{h}^{\mu\nu} = 16\pi \partial_{\nu}T^{\mu\nu}[/tex]
Since we can swap the order of partial differentiation this becomes:
[tex]-\partial_{\alpha}\partial^{\alpha}\left(\partial_{\nu}\bar{h}^{\mu\nu}\right)= 16\pi \partial_{\nu}T^{\mu\nu}[/tex]
Now what I want to proof is that [tex]\partial_{\nu}\bar{h}^{\mu\nu} = \partial^{\nu}\bar{h}_{\mu\nu}[/tex]
I think that is true because [tex]\partial_{\gamma}\bar{h}^{\mu\nu} = - \partial^{\gamma}\bar{h}_{\mu\nu}[/tex]. So if I just replace [itex]\gamma[/itex] by [itex]\nu[/itex] this should imply that the divergence of T vanishes.
But I don't know for sure if I could just replace [itex]\gamma[/itex] by [itex]\nu[/itex]!
Thanks in advance!
Last edited: