Link between Kraus operators and PVMs

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In summary, Kraus operators and Positive Operator-Valued Measures (PVMs) are both fundamental concepts in quantum mechanics that describe the evolution of quantum states and measurements, respectively. Kraus operators provide a mathematical framework for modeling the effects of noise and decoherence in quantum systems through a set of operators that act on the state space, leading to a mixed state. On the other hand, PVMs represent the outcomes of measurements in quantum mechanics, where each outcome is associated with a positive operator that corresponds to the measurement's probability. The relationship between the two lies in their ability to represent quantum processes: Kraus operators can be derived from PVMs when considering the impact of measurements on the system's state, establishing a connection between the dynamics of
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Question about how to find kraus operators from a pvm that generates a given POVM:
can you always find two subsystems and an observable such that tracing out the result of the measurement over one of those subsystems you get the action of the Kraus operators that generates a given POVM?
I'm sorry if this discussion may be dumb.

Is this a way to find a family of kraus operators that generates a given POVM from a PVM?

Assume that you have a POVM given by the family of operators ##\{E_i\}_i##. Then it is possible to find a PVM that generates the given POVM by this procedure:
It is possible to find two subsystems S1 and S2 with spaces respectively ##\mathcal{H}_1## and ##\mathcal{H}_2## and an observable ##M## with spectral projectors ##\{P_k\}_k## and eigenvalues ##\lambda_i ##(let ##\Omega:=\bigcup_i \lambda_i##, let ##S## be the state space). Suppose for example that S2 is ancillary. Suppose moreover that the joint state of the system is ##\rho## and the reduced state of S1 is ##\rho_1=Tr_2(\rho)##.

##\forall i## the Kraus operators will then be defined by this action:
$$A_i: \frac{A_i\rho_1A_i^*}{Tr(A_i\rho_1A_i^*)}=Tr_2(\frac{\sum_{j\in J(i)} P_j \rho P_j}{Tr(\sum_{j\in J(i)} P_j \rho)}) $$

This must hold ##\forall \rho \in S,\rho_1=Tr_2(\rho)##.
Where ##J(i): J(i)\cap J(j)=\emptyset## ##\forall i\neq j##, ##\bigcup_i J(i)=\Omega## is a partition. (I ask for the existence of this partition because the cardinality of the family ##\{E_i\}_i## and of ##\{P_k\}_k## may be different so that we need to cluster some outcome together. I don't know if this is necessary)
 

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