Location of the magnetopause using Chapman-Ferraro equation

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  • #1
Kovac
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Hello,

Lets say you need to calculate the location of the magnetopause subsolar point on earth and you only have this information:

> Solar wind proton number density: 10 cm−3

> Solar wind speed: 700 km s−1

Chapman_ferraro equations:

What is the difference between the above chapman-ferraro equations? Why does one of them have 2^1/3 in front and one doesnt? What does the "pl" & "E" stand for?

Which one is more applicable to my case scanario?
 

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  • #2
It might help to know what source those two equations came from.
 
  • #3
My suspicion is that the simple CF equation gives the midday (subsolar) radius, and that the added term of; 2^(1/3) = 1.26; gives the dawn or dusk radius.
 
  • #4
Ibix said:
It might help to know what source those two equations came from.
These equations are coming from lecture slides.
 
  • #5
Baluncore said:
My suspicion is that the simple CF equation gives the midday (subsolar) radius, and that the added term of; 2^(1/3) = 1.26; gives the dawn or dusk radius.
So if you want realistic values, is it the second equation to be used? Because both give different results
 
  • #6
Kovac said:
Because both give different results
They are different because they are applied at different times of the day.
The magnetopause is not a spherical surface with one radius.
 
  • #7
Ibix said:
It might help to know what source those two equations came from.
Here are both equations mentioned in the slides.

 

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  • #8
Baluncore said:
They are different because they are applied at different times of the day.
The magnetopause is not a spherical surface with one radius.
Alright, could you help me understand what the signs in the denominator stands for.
What is the B in the numerator?
I assume the last term in the denominator is the solar wind velocity, the middle term pressure? And the u0 term is what?
 
  • #9
https://en.wikipedia.org/wiki/Magnetopause

According to this link the p= density of the solar wind, v = velocity, B=magnetic field strength of the planet.
How do I get the μ0? Can I get it through the proton number density?
 
  • #11
Kovac said:
https://en.wikipedia.org/wiki/Magnetopause

According to this link the p= density of the solar wind, v = velocity, B=magnetic field strength of the planet.
How do I get the μ0? Can I get it through the proton number density?
##B_{E}## and ##\mu_{0}## characterize the magnetic properties of the planet. The magnetic field of the Earth can be modeled as a magnetic dipole (https://en.wikipedia.org/wiki/Dipole_model_of_the_Earth's_magnetic_field), with the value of the field at the Earth's surface along the equator taking the value ##B_{E}=3.12\times10^{-5}\text{ tesla}##. And the magnetic permeability of vacuum, ##\mu_{0}=1.26\times10^{-6}{\rm \ N/A^{2}}##, is a basic constant of electromagnetism.
 
  • #12
renormalize said:
##B_{E}## and ##\mu_{0}## characterize the magnetic properties of the planet. The magnetic field of the Earth can be modeled as a magnetic dipole (https://en.wikipedia.org/wiki/Dipole_model_of_the_Earth's_magnetic_field), with the value of the field at the Earth's surface along the equator taking the value ##B_{E}=3.12\times10^{-5}\text{ tesla}##. And the magnetic permeability of vacuum, ##\mu_{0}=1.26\times10^{-6}{\rm \ N/A^{2}}##, is a basic constant of electromagnetism.
Are you sure about u0? Because it seems it should be 4pi * 10^-7 as it is the magnetic permiability of free space:
http://www.sp.ph.imperial.ac.uk/~mkd/AdvancedOption3solutions.pdf
 

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  • #13
Here are the first 4 pages of chap-8, The Handbook of Geophysics and Space Environments.
It defines the CF equation you should use and the variables.
 

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  • #15
renormalize said:
Try multiplying out ##4\times 3.14159\times 10^{-7}##. What do you get?
Yes correct, my bad!
 
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  • #16
Baluncore said:
Here are the first 4 pages of chap-8, The Handbook of Geophysics and Space Environments.
It defines the CF equation you should use and the variables.
So in the equation density p= mass of proton x proton density of the solar wind x 1000 000 (conversion between kgcm^-3 to kgm^-3).
B = M/r^3 where M= magnetic dipole of the planet in question, r= radius of the planet in question.
μ0= 4pi x 10^-7 Vs/Am [magnetic permiability of free space]
u= solar wind velocity.

But I still dont understand why the second equation has 2^1/3 in front? Which one is more correct if you want to calculate for earth?
 
  • #17
Kovac said:
But I still dont understand why the second equation has 2^1/3 in front? Which one is more correct if you want to calculate for earth?
In post #7, the lower RHS of your attachment reads, as best as I can OCR;
"Assuming B=0 In the magnetosheath the induced Bmp, must cancel the geomagnetic dipole field in this region. This yields

Bmp = Bdipole(Rmp)

However, just inside the magnetosphere, B will increase the total B to

B = 2⋅Bdipole⋅(Rmp) = 2^(1/3) * ....
"
Do you want the Rmp, or do you want B ?
 

Related to Location of the magnetopause using Chapman-Ferraro equation

What is the Chapman-Ferraro equation?

The Chapman-Ferraro equation is a theoretical model used to describe the distance to the magnetopause, which is the boundary between a planet's magnetosphere and the solar wind. The equation takes into account the balance between the pressure exerted by the solar wind and the magnetic pressure from the planet's magnetic field.

How is the location of the magnetopause determined using the Chapman-Ferraro equation?

The location of the magnetopause is determined by equating the dynamic pressure of the solar wind to the magnetic pressure of the planet's magnetic field. The Chapman-Ferraro equation typically has the form \( r_m = \left( \frac{B_0^2 R_0^6}{8 \pi P_{sw}} \right)^{1/6} \), where \( r_m \) is the distance to the magnetopause, \( B_0 \) is the magnetic field strength at the planet's surface, \( R_0 \) is the planet's radius, and \( P_{sw} \) is the solar wind pressure.

What factors influence the position of the magnetopause?

The position of the magnetopause is influenced by several factors, including the strength of the planet's magnetic field, the solar wind pressure, and the orientation of the interplanetary magnetic field (IMF). Variations in solar wind conditions, such as changes in velocity and density, can cause the magnetopause to move closer to or further from the planet.

How accurate is the Chapman-Ferraro equation in predicting the magnetopause location?

The Chapman-Ferraro equation provides a good first-order approximation of the magnetopause location but has limitations. It assumes a simplified model of the solar wind and the planet's magnetic field. Real-world conditions, such as fluctuations in solar wind pressure and complex magnetic field interactions, can cause deviations from the predicted location.

Can the Chapman-Ferraro equation be applied to all planets with magnetic fields?

Yes, the Chapman-Ferraro equation can be applied to any planet with a significant magnetic field and a magnetosphere. However, the specific parameters in the equation, such as the magnetic field strength and the planet's radius, will differ for each planet. Adjustments may also be needed to account for unique planetary conditions and solar wind interactions.

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