- #36
LuculentCabal
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SW VandeCarr said:Hello LuculentCabal.
Using your formula, H would be random variable over the set {0, 1, 1.58, 2, 2.33, 2.59} assuming a uniform probability distribution of die face outcomes and a fixed L=1. Is this what you want? N as you define it, is the number of (distinct) characters in the set for which H is determined. This number is determined by the result of the die throw. We are NOT talking about the set of possible outcomes for the die throw which have N=6 and a uniform P=1/6. In this case H is constant and equals 2.59 for L=1.
OK, I am starting to confuse myself here.
//-------------------------------Begin Brain Storm----------------------------------
Letting L = 1:
If N were a six-sided fair-die throw, there would be six possible outcomes so N would be six. In this case, H would just be 2.59.
However, if you threw a six-sided fair-die to determine the number of sides on your fair-die N, then H would be a random variable over the set {0, 1, 1.58, 2, 2.33, 2.59}
//-------------------------------End Brain Storm----------------------------------
Perhaps I am confusing random variables and random processes, but those are details for another thread. If this brainstorm is correct, then I will have no further questions/comments for this thread.
Thank you all again. It has been greatly appreciated.
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