Logarithmic Differentiation with Respect to y

In summary, the conversation discusses differentiating the expression log((x+(x^2+y^2)^0.5)/(-x+(x^2+y^2)^0.5)) with respect to y. The conversation mentions using the chain rule and treating x as a constant to simplify the derivative.
  • #1
captainjack2000
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Homework Statement


I am trying to differentiate log((x+(x^2+y^2)^0.5)/(-x+(x^2+y^2)^0.5)) with respect to y


Homework Equations



I know that d/dx of ln(x) = 1/x but i am getting really confused when it comes to differentiating wrt to y?

Can I have some help please!

The Attempt at a Solution

 
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  • #2
Use the chain rule

[tex]\frac{d}{dy}= \frac{dx}{dy}*\frac{d}{dx}[/tex]

So if you had to differentiate ln(x) w.r.t y

[tex]\frac{d}{dy}(lnx)= \frac{dx}{dy}*\frac{d}{dx}(lnx) = \frac{1}{x}*\frac{dx}{dy}[/tex]
 
  • #3
The argument is [tex]\frac{x+\sqrt{x^2+y^2}}{-x+\sqrt{x^2+y^2}}[/tex]

So when differentiating with respect to y it looks like [tex]\frac{a+\sqrt{a+y^2}}{-a+\sqrt{a+y^2}}[/tex]

where x is just treated as some constant a

So you just use the chain rule for that derivative

Does that look a little less confusing?
 

FAQ: Logarithmic Differentiation with Respect to y

What is sticky differentiation?

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How does sticky differentiation relate to stem cells?

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