- #1
craig100
- 8
- 0
Hello there, I am wondering if you could offer some help on this questoin, I have been attempting to work through it, however cannot see exactly what route I should be taking to try and solve it;
Without using a calculator or table, show that;
2 < log(3) 25 < 3 (log to the base 3 of 25)
and hence find the ceiling of log(3) 75
Also calculate log(5) 75 in terms of log(3)5
Thankyou for any help you can provide.
Craig :)
Edit:
Sorry i forgot to mention, what i have done so far is;
Shown that 3^3 = 27 and 3^2 = 9, this is simply setting log(3)x = 3 and 2 and i get a values in which 25 lies in
9 < 25 < 27
Without using a calculator or table, show that;
2 < log(3) 25 < 3 (log to the base 3 of 25)
and hence find the ceiling of log(3) 75
Also calculate log(5) 75 in terms of log(3)5
Thankyou for any help you can provide.
Craig :)
Edit:
Sorry i forgot to mention, what i have done so far is;
Shown that 3^3 = 27 and 3^2 = 9, this is simply setting log(3)x = 3 and 2 and i get a values in which 25 lies in
9 < 25 < 27
Last edited: