- #1
bluestar
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I have worked out the total spin for the elements up to Neon however I hit a snag with Nitrogen and Fluorine.
The shell sequence of nitrogen 7N7 is 1s2, 2s2, 2p3 for both the proton and neutron and the total angular spin is 1
Likewise, Fluorine 9F10 is 1s2, 2s2, 2p5 for the proton and 1s2, 2s2, 2p6 for the neutron and the total angular spin is ½
In the nitrogen isotope it would appear that the 3 protons and neutrons are not paired and occupy separate states in the 2p shell. Thus the total orbital angular momentum would be 3 and the total spin would be 3/2 for the protons and additional for the neutrons suggesting the total angular momentum of 9 which is wrong.
So do 2 of the protons in different states in the 2p shell pair up their orbital and spin angular momentum? Likewise do 2 of the neutrons in the 2p shell pair up their orbital and spin angular momentum? If so, this would leave yield an orbital momentum of 1 for the proton and 1 for the neutron; likewise, the spin of the two separate nucleons sum up to 1. This would then yield a total angular momentum of 2 + 1 = 3 with is also wrong.
The only way I can see to achieve a total angular momentum of 1 is if the spin of the proton and neutron were both negative, which I considered wrong because unpaired particle spin were always positive. So can an unpaired particle have a negative spin?
With respect to 9F10 there are 2 sets of paired protons plus 1 separate in the 2p shell and all neutrons are paired. This would produce an orbital angular momentum of 1 and a spin of ½ for a total of 3/2; however JANICE indicates this isotope has only ½ spin suggesting the proton spin was -1/2.
Can anyone shed any light on the total spin of these two isotopes?
The shell sequence of nitrogen 7N7 is 1s2, 2s2, 2p3 for both the proton and neutron and the total angular spin is 1
Likewise, Fluorine 9F10 is 1s2, 2s2, 2p5 for the proton and 1s2, 2s2, 2p6 for the neutron and the total angular spin is ½
In the nitrogen isotope it would appear that the 3 protons and neutrons are not paired and occupy separate states in the 2p shell. Thus the total orbital angular momentum would be 3 and the total spin would be 3/2 for the protons and additional for the neutrons suggesting the total angular momentum of 9 which is wrong.
So do 2 of the protons in different states in the 2p shell pair up their orbital and spin angular momentum? Likewise do 2 of the neutrons in the 2p shell pair up their orbital and spin angular momentum? If so, this would leave yield an orbital momentum of 1 for the proton and 1 for the neutron; likewise, the spin of the two separate nucleons sum up to 1. This would then yield a total angular momentum of 2 + 1 = 3 with is also wrong.
The only way I can see to achieve a total angular momentum of 1 is if the spin of the proton and neutron were both negative, which I considered wrong because unpaired particle spin were always positive. So can an unpaired particle have a negative spin?
With respect to 9F10 there are 2 sets of paired protons plus 1 separate in the 2p shell and all neutrons are paired. This would produce an orbital angular momentum of 1 and a spin of ½ for a total of 3/2; however JANICE indicates this isotope has only ½ spin suggesting the proton spin was -1/2.
Can anyone shed any light on the total spin of these two isotopes?