- #1
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Hello, I am trying to prove eq 2.13 in srednicki:
[tex]\delta \omega _{\mu\nu}U(\Lambda)^{-1}M^{\mu\nu}U(\Lambda) = \delta \omega _{\mu\nu}\Lambda^\mu{}_{\rho}\Lambda^\nu{}_{\sigma}M^{\rho\sigma}[/tex]
where we have expanded the following and comparing the linear term:
[tex]U(\Lambda)^{-1}U(\Lambda)^{*}U(\Lambda) = U(\Lambda^{-1}\Lambda ^{*}\Lambda) [/tex]
and
[tex]\Lambda^{*} = 1 +\omega [/tex]
(omega is of course antisymmetric)
and
[tex]U(1+ \delta \omega ) = I + \dfrac{i}{2}\delta \omega _{\mu\nu}M^{\mu\nu}[/tex]
Now I get something like:
[tex]\delta \omega _{\mu\nu}U(\Lambda)^{-1}M^{\mu\nu}U(\Lambda) = U(1+\Lambda^{-1}\delta \omega\Lambda )[/tex]
by just straightforward computation of
[tex]U(\Lambda^{-1}\Lambda ^{*}\Lambda) [/tex]
and now I am stuck badly :-(
[tex]\delta \omega _{\mu\nu}U(\Lambda)^{-1}M^{\mu\nu}U(\Lambda) = \delta \omega _{\mu\nu}\Lambda^\mu{}_{\rho}\Lambda^\nu{}_{\sigma}M^{\rho\sigma}[/tex]
where we have expanded the following and comparing the linear term:
[tex]U(\Lambda)^{-1}U(\Lambda)^{*}U(\Lambda) = U(\Lambda^{-1}\Lambda ^{*}\Lambda) [/tex]
and
[tex]\Lambda^{*} = 1 +\omega [/tex]
(omega is of course antisymmetric)
and
[tex]U(1+ \delta \omega ) = I + \dfrac{i}{2}\delta \omega _{\mu\nu}M^{\mu\nu}[/tex]
Now I get something like:
[tex]\delta \omega _{\mu\nu}U(\Lambda)^{-1}M^{\mu\nu}U(\Lambda) = U(1+\Lambda^{-1}\delta \omega\Lambda )[/tex]
by just straightforward computation of
[tex]U(\Lambda^{-1}\Lambda ^{*}\Lambda) [/tex]
and now I am stuck badly :-(