- #1
maverick280857
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Hi
Suppose [itex]\Lambda[/itex] is a Lorentz transformation with the associated Hilbert space unitary operator denoted by [itex]U(\Lambda)[/itex]. We have
[tex]U(\Lambda)|p\rangle = |\Lambda p\rangle[/tex]
and
[tex]|p\rangle = \sqrt{2E_{p}}a_{p}^{\dagger}|0\rangle[/tex]
Equivalently,
[tex]U(\Lambda)|p\rangle = U(\lambda)\sqrt{2E_{p}}a_{p}^{\dagger}|0\rangle[/tex]
Now, by definition,
[tex]|\Lambda p\rangle = \sqrt{2E_{\Lambda p}}a_{\Lambda p}^{\dagger}|0\rangle[/tex]
Therefore it follows that
[tex]\sqrt{2E_{p}}U(\Lambda) a_{p}^{\dagger}|0\rangle = \sqrt{2E_{\Lambda p}} a_{\Lambda p}^{\dagger}|0\rangle[/tex]
or
[tex]U(\Lambda)a_{p}^{\dagger} = \sqrt{\frac{E_{\Lambda p}}{E_p}}a_{\Lambda p}^{\dagger}[/tex]
But apparently the correct expression is
[tex]U(\Lambda)a_{p}^{\dagger}U^{-1}(\Lambda) = \sqrt{\frac{E_{\Lambda p}}{E_p}}a_{\Lambda p}^{\dagger}[/tex]
Can someone please point out my mistake?
Thanks.
Suppose [itex]\Lambda[/itex] is a Lorentz transformation with the associated Hilbert space unitary operator denoted by [itex]U(\Lambda)[/itex]. We have
[tex]U(\Lambda)|p\rangle = |\Lambda p\rangle[/tex]
and
[tex]|p\rangle = \sqrt{2E_{p}}a_{p}^{\dagger}|0\rangle[/tex]
Equivalently,
[tex]U(\Lambda)|p\rangle = U(\lambda)\sqrt{2E_{p}}a_{p}^{\dagger}|0\rangle[/tex]
Now, by definition,
[tex]|\Lambda p\rangle = \sqrt{2E_{\Lambda p}}a_{\Lambda p}^{\dagger}|0\rangle[/tex]
Therefore it follows that
[tex]\sqrt{2E_{p}}U(\Lambda) a_{p}^{\dagger}|0\rangle = \sqrt{2E_{\Lambda p}} a_{\Lambda p}^{\dagger}|0\rangle[/tex]
or
[tex]U(\Lambda)a_{p}^{\dagger} = \sqrt{\frac{E_{\Lambda p}}{E_p}}a_{\Lambda p}^{\dagger}[/tex]
But apparently the correct expression is
[tex]U(\Lambda)a_{p}^{\dagger}U^{-1}(\Lambda) = \sqrt{\frac{E_{\Lambda p}}{E_p}}a_{\Lambda p}^{\dagger}[/tex]
Can someone please point out my mistake?
Thanks.