- #1
cupid.callin
- 1,132
- 1
I solved it :p
I need help with part (a)
Current in LR circuit, [tex]i = i_o (1 - e^{-t/\tau})[/tex] and [tex]\tau = \frac{L}{R}[/tex]
so, [tex]\frac{dq}{dt} = i_0 (1 - e^{-t/\tau})[/tex]
integrating it is not giving me the correct answer.
Homework Statement
The Attempt at a Solution
I need help with part (a)
Current in LR circuit, [tex]i = i_o (1 - e^{-t/\tau})[/tex] and [tex]\tau = \frac{L}{R}[/tex]
so, [tex]\frac{dq}{dt} = i_0 (1 - e^{-t/\tau})[/tex]
integrating it is not giving me the correct answer.