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xxkylexx
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Homework Statement
A long, straight wire carrying a current of 4.00 A is placed along the axis of a cylinder of radius 0.500 m and a length of 3.00 m. Determine the total magnetic flux through the cylinder.
Homework Equations
Flux = BA
B(long wire) = (((4 * pi) * 10^-7) * I )/ (2 * pi * R)
A(cyclinder) = (2 * pi * r^2) + (2 * pi * r * h)
The Attempt at a Solution
I = 4
r = .5
h = 3
I tried to solve for B by saying:
B = (((4 * pi) * 10^-7) * 4 )/ (2 * pi * .5)
B = 1.6 * 10^-6
and then A:
A = (2 * pi * .5^2) + (2 * pi * .5 * 3)
A = 10.99Flux = (1.6 * 10^-6) * 10.99
Flux = 1.75 * 10^-5----------------------------This is incorrect. Not sure what I am doing wrong here. Any help is very much appreciated. This is due tonight at 11pm EST Thanks much,
Kyle