- #36
hooman
- 22
- 0
explain pleaseMartinCarr said:
Magnetic forces on current-carrying wires
In summary, the conversation discusses a problem involving the direction and magnitude of the resultant magnetic force acting on wire X due to the magnetic fields from wires Y and Z. The direction of the force on X is given as pointing towards X, causing confusion and prompting a discussion on how to approach the problem. Eventually, it is determined that the force per unit length acting on X is 0.50 mN/m, not 0.50 m, and the correct interpretation of the direction of the force is towards the positive x-axis.
- #37
hooman
- 22
- 0
from the question a, i need to know the direction whether it is right or wrong. so, fron the diagram itself we can know whether it is right or wrong. but i don't know how. i cannot determine the direction by using calculation because how can i know the equation have to use minus or addition.Doc Al said:
- #38
hooman
- 22
- 0
the statement is wrong. the right one is the resultant force per unit length is actually acted on Y not on X. it's a mistake in typing the question. sorry. so how to determine the direction whether it's right or wrong?MartinCarr said:
- #39
hooman
- 22
- 0
the statement is wrong. the right one is the resultant force per unit length is actually acted on Y not on X. it's a mistake in typing the question. sorry. so how to determine the direction whether it's right or wrong?Doc Al said:
- #40
Doc Al
Mentor
- 45,586
- 2,304
At least that explains the "towards X" statement.hooman said:
Do you know how to find the force/length between two current-carrying wires? Start there.hooman said:
Try this: Magnetic Force Between Wires
- #41
hooman
- 22
- 0
what does it means by pointing towards X? yes, I do know how to find F/lDoc Al said:
- #42
hooman
- 22
- 0
but, in the question in the link that you gave, i don't know how to do it because the question itself doesn't give any valueDoc Al said:
- #43
MartinCarr
- 10
- 1
As we know a current carrying wire will induce a magnetic field around it. This field will be clockwise around the wire in the direction of current. Both wire Y and Z will exert a force on X.
By looking at the direction of the magnetic field from Y and then Z at the side of X (either into or out of the paper) you can use the hand rules (movement, flux & current) you can work out which way the wire will move.
Using the formula in the attachment you can then calculate the force and hence the direction and value of current in the question.
By looking at the direction of the magnetic field from Y and then Z at the side of X (either into or out of the paper) you can use the hand rules (movement, flux & current) you can work out which way the wire will move.
Using the formula in the attachment you can then calculate the force and hence the direction and value of current in the question.
- #44
Neelima
- 5
- 1
Considering the figure as it is ,
Force on X due to Y is towards left
Force on X due to Z is towards right.
As net force on X is towards left ( see the attachment ).
F(y) > F (z).
F (net) = F(y) - F( z)
50 x 10^(-5) = 25 x 10^ (-5) - (20xI /6) x 10^(-5)
Solving we get negative value for I which is meaningless . In my opinion it should not be.
So direction of current in Z should be downward.
Then due to both Y and Z forces will be towards X.
Force on X due to Y is towards left
Force on X due to Z is towards right.
As net force on X is towards left ( see the attachment ).
F(y) > F (z).
F (net) = F(y) - F( z)
50 x 10^(-5) = 25 x 10^ (-5) - (20xI /6) x 10^(-5)
Solving we get negative value for I which is meaningless . In my opinion it should not be.
So direction of current in Z should be downward.
Then due to both Y and Z forces will be towards X.
