Magnitude of Potential Difference Between Two Points

In summary, a current of 1.2 A flows from A to B. This potential difference is due to the resistors in series and is 5Ω.
  • #1
anomalocaris
23
0
potential diffeence.jpg
1. Homework Statement [/b]

So I found this problem online, and I really do not know how to go about solving it! My professor has done similar problems in class, but it's still a little confusing.

A current of 1.2 A flows from A to B. Therefore, the magnitude of the potential difference between points A and B is approximately

Homework Equations


I know Δv=IR and Ampere/Volt makes an Ω

The Attempt at a Solution



Well, the image attached already gives the answer, it should be 6.0 V. The current is given (1.2 A), so I'm guessing by the units that I must multiply something with Ω to get Volts. Should I add up the resistors?

Thank you!
 
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  • #2
To do this problem, you are going to need to be able to "add" resistors in parallel and series. Need help with that?
 
  • #3
anomalocaris said:
Well, the image attached already gives the answer, it should be 6.0 V. The current is given (1.2 A), so I'm guessing by the units that I must multiply something with Ω to get Volts. Should I add up the resistors?

Sure. Find the equivalent resistance between points A and B. Then see what potential drop occurs across it due to the given current value.
 
  • #4
lewando said:
To do this problem, you are going to need to be able to "add" resistors in parallel and series. Need help with that?


Haha, lewando, yes please!

Would we consider the two 6Ω resistors parallel? And if so, the potential difference there is the same? We are getting to the point where I just smile and nod during the lecture even though I am completely lost!
 
  • #5
  • #6
lewando said:
Well then take a look at the following two websites:
http://www.allaboutcircuits.com/vol_1/chpt_5/1.html (for a definition of series/parallel)
http://en.wikipedia.org/wiki/Series_and_parallel_circuits (for how to combine them)

Give them a read and come back with any questions.

Thank you so much! I just had an epiphany and this is all way less complicated! Thank you to all who replied. And thank you so much, lewando. I wasn't taking the reciprocals of the resistances and so I was adding them incorrectly, but now it all makes much more sense. I ended up with an R_eq of 5Ω, which when multiplied by 1.2 A yields a potential difference of 6 V. Thank you so much!
 

FAQ: Magnitude of Potential Difference Between Two Points

What is the magnitude of potential difference between two points?

The magnitude of potential difference between two points is a measure of the difference in electric potential energy per unit charge between the two points. It is commonly represented by the symbol ΔV and is measured in volts (V).

How is the magnitude of potential difference calculated?

The magnitude of potential difference can be calculated by dividing the change in electric potential energy (ΔU) by the amount of charge (Q) that moved between the two points. This can be expressed as ΔV = ΔU / Q.

What factors affect the magnitude of potential difference between two points?

The magnitude of potential difference is affected by the amount of charge, the distance between the two points, and the presence of any electric fields or resistors in between the points. It is also dependent on the type of material between the points and its conductivity.

How does the magnitude of potential difference relate to electric current?

The magnitude of potential difference is directly related to electric current. The greater the potential difference, the greater the force that pushes charged particles to move from one point to another, resulting in a larger electric current.

What is the significance of the magnitude of potential difference in electrical circuits?

The magnitude of potential difference is a key factor in determining the flow of electric current in a circuit. It is used to calculate the amount of work that can be done by an electric current, and is essential in determining the power and efficiency of electrical devices.

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