Making T the Subject: V*T to the Power n = C

  • Thread starter jamesd2008
  • Start date
  • Tags
    Formula
In summary, the rule is that the logarithm of x^n is n times the logarithm of x. Knowing this, you can calculate the power of x using the equation VT^{n}=C. Additionally, you can also use the parentheses to show that log(T) is also equal to 1/nlog(c/v).
  • #1
jamesd2008
64
0
Hi, could anyone show me how to make T the subject?

V*T to the power n = C

Thanks
 
Engineering news on Phys.org
  • #2
If
[tex]T^n = c[/tex]
then
[tex](T^n)^{1/n} = T = c^{1/n}[/tex]
 
  • #3
Thanks compu, could you just explain the rule as to why it is C^1/n?

Thanks James
 
  • #4
If n=0.3 Then T^3/10 so C would be the 10 root of C to the power of 3. Is that right? or am i getting my indices and power rules wrong?
Thanks for any help offerd

James
 
  • #5
jamesd2008 said:
Thanks compu, could you just explain the rule as to why it is C^1/n?

Thanks James

Knowing that the logarithm of x^n is n times the logarithm of x:

[tex]VT^{n}=C[/tex]

[tex]T^{n}=\frac{C}{V}[/tex]

[tex]log \left[ T^{n} \right] = log \left[ \frac{C}{V} \right] [/tex]

[tex]n log \left[ T \right] = log \left[ \frac{C}{V} \right] [/tex]

[tex]log \left[ T \right] = \frac{1}{n} log \left[ \frac{C}{V} \right] [/tex]

[tex]log \left[ T \right] = log \left[ \left( \frac{C}{V} \right)^{\frac{1}{n}} \right] [/tex]

[tex]T = \left( \frac{C}{V} \right)^{\frac{1}{n}} [/tex]

Many thanks to all for bracket help.
 
Last edited:
  • #6
Thanks Timmay. Great explanation. Just a couple of things i don't get. Why is nLog(T)=Log(c/v) then become log (T)=1/nlog(c/v). And why is not just T^n=c becomes T=nroot of c?

Thanks for all your reply's a great help James
 
  • #7
jamesd2008 said:
Thanks Timmay. Great explanation. Just a couple of things i don't get. Why is nLog(T)=Log(c/v) then become log (T)=1/nlog(c/v).
Because if AB=C then B=C/A?
I.e. primary school algebra :wink:

jamesd2008 said:
And why is not just T^n=c becomes T=nroot of c?
It is. Raising something to the power 1/n is the same as taking the n-th root (cf. a^(1/2) = sqrt(a) = 2root(a)).

[Just realized what the confusion might be: note that my c is not your C... you first have to rewrite V T^n = C to T^n = c to apply what I said. ]
 
  • #8
timmay said:
Can't quite get the hang of brackets still, but you should be able to follow.

Try
Code:
\left( ... \right)
Rather than simply (...). \left[ \right] also works :)
 
  • #9
Like this:
[tex]\left\{ \log\left[ \left(\frac{\left( C \right)}{V} \right)^{\frac{1}{n}} \right] \right\}[/tex]

(click to see the source)
 

FAQ: Making T the Subject: V*T to the Power n = C

1. How do you make T the subject of the formula V*T^n = C?

To make T the subject, divide both sides of the equation by V and then take the nth root of both sides. This will isolate T on one side of the equation.

2. What does the variable n represent in the formula V*T^n = C?

The variable n represents the power to which T is raised. This can be any number, including fractions or negative numbers.

3. What is the significance of the constant C in the formula V*T^n = C?

The constant C represents the value that V*T^n is equal to. In other words, it is the result of the equation and does not change.

4. How can the formula V*T^n = C be useful in scientific research?

This formula can be useful in many areas of science, such as physics, chemistry, and biology. It can help calculate variables, such as time or temperature, in experiments and can also be used to find relationships between different measurements.

5. Are there any limitations to using the formula V*T^n = C?

While this formula can be useful, it is important to keep in mind that it may not apply to all situations. It assumes a constant value of C and may not accurately represent real-world scenarios where variables can change. Additionally, the formula may not be applicable to non-linear relationships between V and T.

Similar threads

Back
Top