- #1
phyzmatix
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Homework Statement
Two curves
[tex]y_1=(\frac{20}{x^2})\sin(\frac{10}{x})[/tex]
and
[tex]y_2=5\cos x[/tex]
intersect in three points in the interval (1,3). Draw the graphs, compute the minimum and maximum points as well as the turning points and show the points of intersection.
2. The attempt at a solution
The second function is straightforward, so my issues arise solely from y1. It's easy enough to see that y1 will be undefined at x=0 and also to determine the y-intercepts in the interval (1,3). My problems start when I try to determine the turning points for y1.
I know that the turning points will be found where
[tex]y'_1=0[/tex]
i.e. where
[tex]\frac{d}{dx}[(\frac{20}{x^2})\sin(\frac{10}{x})]=0[/tex]
[tex](\frac{-40}{x^3})\sin(\frac{10}{x})+(\frac{20}{x^2})\cos(\frac{10}{x})(\frac{-10}{x^2})=0[/tex]
[tex](\frac{-40}{x^3})\sin(\frac{10}{x})+(\frac{-200}{x^4})\cos(\frac{10}{x})=0[/tex]
[tex](\frac{-40}{x^3})[\sin(\frac{10}{x})+(\frac{5}{x})\cos(\frac{10}{x})]=0[/tex]
[tex]\sin(\frac{10}{x})=-(\frac{5}{x})\cos(\frac{10}{x})[/tex]
[tex]x\sin(\frac{10}{x})=-5\cos(\frac{10}{x})[/tex]
But now what? This can be simplified to either
[tex]\tan(\frac{10}{x})=\frac{-5}{x}[/tex]
or
[tex]x\tan(\frac{10}{x})=-5[/tex]
Neither of which help me much as I have no idea how to proceed beyond this point. Assuming I didn't make any mistakes, how do I determine the values of x where y1 will have turning points? Of course, if my reasoning is flawed/I made a mistake somewhere, please let me know.
Your help is appreciated!
phyz