- #1
CarlosMarti12
- 8
- 0
Hello, I am trying to calculate what the margin of error for the standard deviation would be if each data point has a margin of error E. The standard deviation (for 3 data points) is defined as
[itex]σ = \sqrt{\frac{(x_{1}-μ)^{2}+(x_{2}-μ)^{2}+(x_{3}-μ)^{2}}{3}}[/itex]
Where
[itex]μ = \frac{x_{1}+x_{2}+x_{3}}{3}[/itex]
In other words, [itex]x_{n}[/itex] for n = 1, 2, or 3 has a margin of error of ±E. Is there a way to find what the maximum margin of error would be for the standard deviation, given the margin of error for each individual data point? (Notice that the margin of error would affect the mean value of μ as well.)
Any help would be greatly appreciated. Thanks!
[itex]σ = \sqrt{\frac{(x_{1}-μ)^{2}+(x_{2}-μ)^{2}+(x_{3}-μ)^{2}}{3}}[/itex]
Where
[itex]μ = \frac{x_{1}+x_{2}+x_{3}}{3}[/itex]
In other words, [itex]x_{n}[/itex] for n = 1, 2, or 3 has a margin of error of ±E. Is there a way to find what the maximum margin of error would be for the standard deviation, given the margin of error for each individual data point? (Notice that the margin of error would affect the mean value of μ as well.)
Any help would be greatly appreciated. Thanks!