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skaterboy1
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Homework Statement
There are three patchs in which an animal can forage.
Patch 1: Risk of predation is 0. Probability of finding food is 0. Energy value is 0.
Patch 2: Risk of predation is 0.004. Probability of finding food is 0.4 and energy gain is 3.
patch 3: risk of predation is 0.02. Probability of finding food is 0.6 and energy gain is 5.
Foraging in any patch uses one unit of energy reserves. Energy reserves below 4 indicate death. maximum energy capacity for animal is ten units.
Solve this problem for 20 foraging periods to find a patch selection strategy which maximizes the animals probability of survival over this period.
Homework Equations
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The Attempt at a Solution
Three patchs; N=3
States: risk, food findings and energy gain.
action: Choosing patchs 1, 2 or 3.
How do I solve this problem?
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