- #1
lpettigrew
- 115
- 10
- Homework Statement
- Hello, I have a question which I have answered below but I do not think that I have done so correctly. Could someone please advice me how to improve my workings?
1 . Modelling the parachute as a hemisphere, use the following information to calculate the upthrust produced due to the parachute.
ρmars atmosphere = 0.02 kgm^-3
volume of a sphere = 4 / 3 𝜋 𝑟^3
gmars = 3.8 ms^-2
2. Given that Curiosity’s mass equals 900 kg, what was its acceleration once the parachute was
deployed?
- Relevant Equations
- ρmars atmosphere = 0.02 kgm^-3
volume of a sphere = 4 / 3 𝜋 𝑟^3
gmars = 3.8 ms^-2
F=ma
1. ρmars atmosphere = 0.02 kgm^-3
volume of a sphere = 4 / 3 𝜋 𝑟^3
gmars = 3.8 ms^-2
So: Volume of a hemisphere=2/3 𝜋 𝑟^3
r=7.75 m
Archimedes' principle states that the upthrust on an object is equal to the weight of fluid that the body displaces
To find the upthrust produced;
upthrust=weight
upthrust=mg
upthrust=p*V*g
mass=density*volume
mass=0.02*(2/3*𝜋 *7.75^3)
mass=19.498~19.5kg (3.s.f)
upthrust=19.5*3.8=74.09~74.1 N2. Given that Curiosity’s mass equals 900 kg, what was its acceleration once the parachute was
deployed?
Using Newton's Second Law; F=ma
F=mg
a=F/m
a=mg/m
a=(900*3.8)-(19.5*3.8)/900+19.5
a=3345.9N/919.5kg
a=3.6388 ~3.64 ms^-2 (3.s.f)
volume of a sphere = 4 / 3 𝜋 𝑟^3
gmars = 3.8 ms^-2
So: Volume of a hemisphere=2/3 𝜋 𝑟^3
r=7.75 m
Archimedes' principle states that the upthrust on an object is equal to the weight of fluid that the body displaces
To find the upthrust produced;
upthrust=weight
upthrust=mg
upthrust=p*V*g
mass=density*volume
mass=0.02*(2/3*𝜋 *7.75^3)
mass=19.498~19.5kg (3.s.f)
upthrust=19.5*3.8=74.09~74.1 N2. Given that Curiosity’s mass equals 900 kg, what was its acceleration once the parachute was
deployed?
Using Newton's Second Law; F=ma
F=mg
a=F/m
a=mg/m
a=(900*3.8)-(19.5*3.8)/900+19.5
a=3345.9N/919.5kg
a=3.6388 ~3.64 ms^-2 (3.s.f)