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hus8765
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thanks a lotgneill said:If it is static (no motion) then the lengths will not be changing. Look to free body diagrams and tensions instead.
In a compound pulley system, the total mass is evenly distributed among all the connected pulleys and ropes. This means that each pulley and rope will have an equal amount of mass attached to it, resulting in a balanced system.
The formula for calculating the mass needed for static equilibrium in a compound pulley system is: M = F/2, where M is the total mass needed and F is the force applied to the system. This formula assumes that all the pulleys and ropes are frictionless and weightless.
Yes, it is possible for the mass needed for static equilibrium to be less than the applied force in a compound pulley system. This can occur when the number of ropes and pulleys in the system creates a mechanical advantage, resulting in a lower required mass to balance the system.
The more ropes and pulleys in a compound pulley system, the lower the mass needed for static equilibrium. This is because each additional pulley and rope increases the mechanical advantage and reduces the required mass to balance the system.
The accuracy of the calculated mass needed for static equilibrium in a compound pulley system can be affected by factors such as friction in the pulleys and ropes, the weight of the pulleys and ropes themselves, and external forces acting on the system. Additionally, the precision of the measurements and the assumptions made in the calculations can also affect the accuracy of the result.